ohms law
use kirchoff's voltage law around the loop
Ohm's law states that the current in a circuit is inversely proportional to the circuit resistance. There is a single path for current in a series circuit. The amount of current is determined by the total resistance of the circuit and the applied voltage.
Voltage drop due to the resistance present in the series circuit causes voltage split over a series circuit.
Resistance isn't lost. The largest voltage drop will occur across the largest resistance in a series circuit.
The higher the resistance the dimmer the light will become. The voltage drop (current) is proportional to the resistance as seen in the equation V=IR, since voltage remains the same throughout a series circuit if the equivalent resistance goes up the amount of current reaching the lightbulb must go down to equal the voltage thus creating a dimmer lightbulb.
The current through each resistor is equal to the voltage across it divided by its resistance for series and parallel circuits.
voltage drop deviding accure
ohms law calculation for a series circuit - Total Resistance = Total Voltage divided by Total Current
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
At the point of highest resistance.
Current = (Voltage across the circuit) divided by (Total resistance of the circuit). The current is the same at every point in the series circuit.