P=IV and V=IR so subbing V in P=IV you get the equation to use which is P=I2R So rearrange this to get R as the subject you get R= P/ I2 so R= 1000/5 2 = 1000/25= 40 Ohms
A 3 heat switch enables two elements for example of 1kw, to give out 100% power, 50% power and finally 25%. That equates to two 1kw elements in parallel. (100%) One 1kw element on power only. (50%) And finally both 1kw elements in series. (25%)
1Kw=1000watt
1kw electric power
1kW = 1.341 hp
1kW is 1.341hp
Electric rating of 1Kw
1kW : 3,412.142 BTU/hr
1kW = 1000W 50kW = 50000W
A 1000 W heater would have more resistance compared to a 100 W bulb. The higher the power rating of an electrical device, the lower its resistance, as resistance is inversely proportional to power. So, the 1000 W heater would have lower resistance than the 100 W bulb.
1kW = 20,472.852 BTU/hr
1kW is 3,412.13 BTU/hr
The meter can only handle 1 amp, so you need to put a resistance in parallel with the meter that will take 99% of the current. So a 1.01 ohm resistor needs to be put in parallel. BUT don't actually do this. The internal resistor can dissipate (P = I^2*R) 100 watts. This resistor you're putting in parallel needs to be able to dissipate near 1kW. What voltage is this? It might be much easier to measure voltage drop across a (known) resistive element in the circuit to determine the current. Depending on your setup, this might be more accurate as well.