The resistance is equal to the voltage-squared divided by the power. So a 1kW heater is 52.9 ohms, a 100 watt bulb is 529 ohms.
The basic formula is W = V^2 / R
Depending on the length of the wire difference between the shot and long wire, in technical fact the bulb would be brighter if a shorter wire was used, but not that much brighter. Energy is used up as it travels along wires.
Considering that everything else is equal, ie. glass, incoming wire. If you are talking only about the filament wire that is attached between the Two poles inside the bulb, the answer is friction. The thicker the wire the less resistance it will have and will allow more electricity to pass without creating friction, the friction is what causes the wire to heat up and glow.
It would not work because when two things are in series the same current has to pass through both. Normally an electric light takes much less current than an electric heater and therefore the light has more resistance. Most of the voltage would appear across the light bulb, so you would have a slightly dimmed bulb and a heater giving out very little heat. It would work if both devices were identical. Electricity supplies use a constant voltage, e.g. 120 v or 240 v, and all applicances are connected in parallel across the supply.
A small resistance in the coil will yield greater heat output in an electric heater. This is because a small resistance allows for a larger current to flow through the coil, which in turn generates more heat due to the increased power dissipation (P = I^2 * R).
The resistance value for an LED bulb in a 12V DC circuit can vary depending on the specific LED bulb used. Generally, LEDs have very low resistance values due to their semiconductor nature. It is more common to use a current-limiting resistor in series with the LED to control the current and prevent damage to the LED.
The thickness of the wire (resistance) and length of the wire can affect the brightness of the bulb. Thicker wire has less resistance, allowing more current to flow and producing a brighter bulb. Shorter wire lengths also reduce resistance, resulting in a brighter bulb due to more current flowing through it.
An incandescent bulb has a filament that has a resistance. The value of the resistance determines the current that will flow for a given supply voltage. The heat generated by the current flowing through the filament gives off light. As the resistance of the filament decreases the current increases and you get more light.
Depending on the length of the wire difference between the shot and long wire, in technical fact the bulb would be brighter if a shorter wire was used, but not that much brighter. Energy is used up as it travels along wires.
Added resistance in a circuit will decrease the current flowing through the circuit, resulting in a decrease in the brightness of the bulb. This is because the bulb's brightness is directly proportional to the current passing through it. More resistance means less current, which leads to reduced brightness.
When the current increases as a voltage is applied to the bulb it causes the bulb's special wire filament to get so hot that it glows very brightly. The heating causes changes in the normal electron lattice of the filament, creating more barriers to the flow of the electrons and therefore the resistance of the wire increases as it gets hotter.
Absolutely the more Resistance is put in series the less current Will flow.
R1=v square/50 R2 = v square/25 = v square/25 multiplied by 2/2 = 2v square/50 R2 = 2 multiplied by R1 R2 is twice more than R1
There is no particular reason why a motor should have a bigger resistance than a bulb. A motor's resistance must depend on what current it draws at the particular voltage it was designed to run on. Equally, a bulb's resistance must depend on what current it draws at the particular voltage it was designed to run on. A particular motor may have a higher resistance than one kind of bulb but that same motor may have a lower resistance than another kind of bulb.
Thicker or shorter wires will have lower resistance, allowing more current to flow and increasing the brightness of the bulb. Thinner or longer wires will have higher resistance, reducing current flow and dimming the bulb. Ultimately, the length and thickness of the wire will impact the overall electrical resistance in the circuit, affecting the brightness of the bulb.
The engineered electrical resistance the higher the number the more resistance it can handle and vise versa.
Considering that everything else is equal, ie. glass, incoming wire. If you are talking only about the filament wire that is attached between the Two poles inside the bulb, the answer is friction. The thicker the wire the less resistance it will have and will allow more electricity to pass without creating friction, the friction is what causes the wire to heat up and glow.
The electrical resistance of a light bulb increases when it is turned on As a resistor, the tungsten light bulb has a positive resistance coefficient. This means that the electrical resistance goes up when the filament becomes hot. For example, a 100 watt light bulb operated at 120 volts - it does not matter if it is AC or DC for this calculation - will have a resistance of 144 ohms when hot and draw .833 ampere. When cold the filament typically has a resistance of only 10 ohms which increases as the filament heats up.