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Young, older, and oldest rock
The Law of Cross-Cutting Relationships would be used here. If a fault cuts across a rock unit, it is younger than that rock unit. If a fault cuts across a series of rocks, but suddenly stops at a rock unit, then that rock unit which the fault stops at is younger than the fault. So let's say the order of rocks (from top to bottom), is A B C D. If the fault cuts across B C and D, but not A, then the age of the fault is sometime between A and B. If you know the absolute ages of A and B (let's say, rock A is 100 million years old and rock B is 200 million years old), then the age of the faulting is between 100 and 200 million years ago.
Given the law of superposition and assuming an undisturbed "pancake" stratigraphy each successive layer is younger than the the underlying one. Therefore, the fault is the 'youngest' feature in the system because the rocks need to form first in order for a fault to truncate them.
Their ages
Geologists generally know the age of a rock by determining the age of the group of rocks, or formation, that it is found in. The age of formations is marked on a geologic calendar known as the geologic time scale. Development of the geologic time scale and dating of formations and rocks relies upon two fundamentally different ways of telling time: relative and absolute.
Young, older, and oldest rock
How could the rock be faulted if it came after the faulting? It wouldn't be there to fault. So therefore, what ever the fault cuts through, it must be younger than it in order for it to be able to cut the rock in the first place.
The Law of Cross-Cutting Relationships would be used here. If a fault cuts across a rock unit, it is younger than that rock unit. If a fault cuts across a series of rocks, but suddenly stops at a rock unit, then that rock unit which the fault stops at is younger than the fault. So let's say the order of rocks (from top to bottom), is A B C D. If the fault cuts across B C and D, but not A, then the age of the fault is sometime between A and B. If you know the absolute ages of A and B (let's say, rock A is 100 million years old and rock B is 200 million years old), then the age of the faulting is between 100 and 200 million years ago.
100 year old
100 year old
What is the relative age of a fault that cuts across three horizontal sedimentary rock layers?A. The fault is older than the middle layer. B.The fault is younger than all the layers it cuts across.C. The fault is the same age as the top layer. D. The fault is older than all the layers it cuts across == ==
Given the law of superposition and assuming an undisturbed "pancake" stratigraphy each successive layer is younger than the the underlying one. Therefore, the fault is the 'youngest' feature in the system because the rocks need to form first in order for a fault to truncate them.
Younger than all three sediments.
The undisturbed rock layers are horizontal and in order of age from youngest nearest the surface to oldest at the bottom of the rock unit.
Their ages
The fault will be younger than the rocks it faulted (cross-cutting relationships).
Information needed for a reverse mortgage calculator would be; the value of the property, the mortgage balance remaining, and the age of the youngest owner of the property.