Please mention the reaction.
Copper(II) Oxide: CuO reaction with Nitric Acid: CuO + 2 HNO3 => Cu(NO3)2 + H2O Copper(I) Oxide: Cu2O reaction with Ntric Acid: Cu2O + 2HNO3 => CuNO3 + H2O
The balanced chemical equation for the reaction between copper(II) oxide (CuO) and sulfuric acid (H2SO4) is: CuO + H2SO4 → CuSO4 + H2O
6,26 g CuO are obtained.
The reaction between copper oxide (CuO) and sulfuric acid (H2SO4) produces copper sulfate (CuSO4) and water (H2O). The balanced chemical equation for this reaction is: CuO + H2SO4 -> CuSO4 + H2O
The thermal decomposition in this case is: CuCO3 -------------CuO + CO2
no reaction
No.
6,26 g CuO are obtained.
The reaction is;CuSO4 = CuO + SO3
Copper(II) Oxide: CuO reaction with Nitric Acid: CuO + 2 HNO3 => Cu(NO3)2 + H2O Copper(I) Oxide: Cu2O reaction with Ntric Acid: Cu2O + 2HNO3 => CuNO3 + H2O
To find the number of moles, first calculate the molar mass of CuO by adding the atomic masses of copper (Cu) and oxygen (O) together. Then, divide the given mass of CuO (3.2g) by the molar mass to get the number of moles.
The balanced chemical equation for the reaction between copper(II) oxide (CuO) and sulfuric acid (H2SO4) is: CuO + H2SO4 → CuSO4 + H2O
The chemical decomposition is:CuSO4------ CuO + SO3
CuO + CH3OH --> HCHO + Cu + H2O
The fizzing occurs because the reaction between copper II oxide and sulfuric acid produces carbon dioxide gas as a byproduct. This gas is released as bubbles, causing the fizzing effect. The chemical reaction can be represented as: CuO + H2SO4 → CuSO4 + H2O + CO2.
The thermal decomposition in this case is: CuCO3 -------------CuO + CO2
11 g hydrogen are needed.