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how many moles are there in 56.0 grams of silver nitrate?
The concentration is 2 M.
The answer is 31 g/L nitrate.
The percentage of silver nitrate by weight is 100[5.48/(5.48 + 25.0)] = 18.0 %, to the justified number of significant digits.
The formula of lead (II) nitrate is Pb(NO3)2. This shows that in any solution of lead nitrate only, the molar concentration of nitrate ions will be twice as much as the molar concentration of lead (II) nitrate. Molar concentration is defined as number of moles per liter of solution, and 800 mL is the same as 0.800 liters. Therefore the molar concentration of nitrate ions in the specified solution will be 2(0.027823/0.800) or 6.96 X 10-2 . Only three significant digits are justified because that is the number of digits in 800.
how many moles are there in 56.0 grams of silver nitrate?
The concentration is 2 M.
the word chemical equation islead nitrate + sodium chromate --> sodium nitrate + lead chromate
the word chemical equation islead nitrate + sodium chromate --> sodium nitrate + lead chromate
The concentration is 2 M.
Silver chromate is not soluble in water.
The answer is 31 g/L nitrate.
The percentage of silver nitrate by weight is 100[5.48/(5.48 + 25.0)] = 18.0 %, to the justified number of significant digits.
it turns into potassium nitrate and barium chromate K2CrO4 + Ba(NO3)2 --> 2KNO3 + BaCrO4
The formula of lead (II) nitrate is Pb(NO3)2. This shows that in any solution of lead nitrate only, the molar concentration of nitrate ions will be twice as much as the molar concentration of lead (II) nitrate. Molar concentration is defined as number of moles per liter of solution, and 800 mL is the same as 0.800 liters. Therefore the molar concentration of nitrate ions in the specified solution will be 2(0.027823/0.800) or 6.96 X 10-2 . Only three significant digits are justified because that is the number of digits in 800.
by the reaction of lead nitrate with potassium chromate or potassium dichromate
The concentration is 2 mol/L.