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The formula of lead (II) nitrate is Pb(NO3)2. This shows that in any solution of lead nitrate only, the molar concentration of nitrate ions will be twice as much as the molar concentration of lead (II) nitrate.

Molar concentration is defined as number of moles per liter of solution, and 800 mL is the same as 0.800 liters. Therefore the molar concentration of nitrate ions in the specified solution will be 2(0.027823/0.800) or 6.96 X 10-2 . Only three significant digits are justified because that is the number of digits in 800.

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Q: When 0.027823 mol of lead II nitrate is dissolved in enough water to make 800 mL of solution what is the molar concentration of nitrate ions?
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