Different horsepower motors come in many different physical sizes.
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Need motor voltage, amperage and phase to give you an anwer.
To answer this question, wire size is rated in the amount of amperage that it can legally carry. The formula to find amperage when the HP is known is I = HP x 746/1.73 x E x %eff x pf. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92. Amps = 30 x 746 = 22380 = 22380/ 1.73 x 480 x .87 x .87 = 22380/629 = 35.6 amps. The electrical code states that a motor conductor has to be rated at 125% of the motors full load amperage. 35.6 x 125% = 44.5 A #8 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 50 and 55 amps respectively.
To answer this question accurately the amperage of the motor must be given. Using 746 watt equals one horsepower will not be as accurate but will be close to the correct wire size. The equation for amps when HP is known is I = HP x 746/E x %eff x pf. Amps = 746 x 3 = 2238/240 x .84 x .86 = 2238/173 = 13 amps. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92. A #8 copper conductor will limit the voltage drop to 3% or less when supplying 13 amps for 400 feet on a 240 volt system. The electrical code book states that a 3 HP motor on 230 volts draws 17 amps. If this is closer to what you pump draws then the wire size will be; A #6 copper conductor will limit the voltage drop to 3% or less when supplying 17 amps for 400 feet on a 240 volt system.
A single-phase induction motor uses variable amounts of current depending on the load etc. but on a 240 v system you should allow 7 amps per horsepower, so 35 amps for 5 HP.
It depends on the horse-power of the engine. 220 cc would be about 8-10 HP, equivalent to a 6-8 HP electric motor. But a small petrol engine is usually not used at full power continuously, so manybe a 5 HP motor would do the job.
If the electric motor requires 2 hp to run, then you need to supply it with no less than 1,492 watts of electric power. It makes no difference what job the motor is used for.
A 5 kW generator would turn it over but if the full 30 hp of mechanical power is needed, that would require about 30 kW of electric power from the generator.
The right size for an electric outboard motor for a 10 foot fishing boat seems to be 4 - 5 - 6 hp, 8 - 9.9 hp or 15 - 20hp. It simply depends on what kind of fishing boat it is.
All motors draw less current when their load reduces.
5-10 hp gas motor should be more than adequate. An electric motor would alos work well, especially on small lakes or sloughs without significant current.
20 amp should do ya.
$1
Best advice I can give is 'Buy one' you have not even specified what rpm you require.
190 cc. is about 5 hp.
The flow of 5 hp motor pump is around 90 GPM.
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