16 bit and 32 bit are the most common values. See sizeof.
sizeof (int)
(platform dependent, often 2 or 4)
the size of an ant is 5 center metres long.
The storage size of an int in C is loosely defined, and may be either 2 bytes or, more commonly, 4 bytes. Whether or not it is defined as const won't affect the size.
There is no boolean in C, we usually use int/short/char to store logical values.
Data-type (short for integer).
for C: sizeof (int), often 2 or 4 bytefor Java: 4 byte
It depends on the programming language, the compiler, and the machine architecture. In C, the size of short int and int is not mandated by the language. Often, on 32-bit machines, 'int' will be 32-bit, while 'short int' may be 16-bit. But the only thing the language promises is that short int will be no larger than int.
The total number of bytes allocated to the union will be the same number as would have been allocated if instead of the union was declared the largest member of the union. For example, if you declared: union myUnion { char c; int i; double d; } u;, then the space allocated to u will be the size of a double.
The storage size of an int in C is loosely defined, and may be either 2 bytes or, more commonly, 4 bytes. Whether or not it is defined as const won't affect the size.
sizeof (int) will tell you (in bytes). It's often 2, 4 or 8 bytes.
There is no boolean in C, we usually use int/short/char to store logical values.
printf ("sizeof (int) is %d bytes", (int)sizeof (int)); Most likely it will be 2 or 4.
Data-type (short for integer).
for C: sizeof (int), often 2 or 4 bytefor Java: 4 byte
#include
It depends on the programming language, the compiler, and the machine architecture. In C, the size of short int and int is not mandated by the language. Often, on 32-bit machines, 'int' will be 32-bit, while 'short int' may be 16-bit. But the only thing the language promises is that short int will be no larger than int.
It depends on the type of integer (such as long, short, int and char) and the specific implementation of C++. The only guarantee is that a char must occupy one byte (sizeof(char)==1). An int is typically 32-bits (4 bytes), but only sizeof(int) can tell you for sure.
It depends on both the programming language and the computer architecture, but it is generally assumed to be 2 bytes/16 bits.In C/C++, an implementation may decide to skip shorts as a separate type and make the short the same as an int, normally 4 bytes/32 bits.See related link for some more details.
In C++, dynamically allocated variables are best encapsulated in a class. In this way, the variable is automatically deleted when the object falls from scope. #include<iostream> class f () { int* p; public: f (const int i=0): p {new int{i}} {} f (const& f other): p {new int{*other.p;}} {} ~f() {delete p; } f& operator=(const f& other) { *p = *other.p; } f& operator= (const int i) {*p=i;} operator int () { return *p; } }; int main() { { f value = 42; // use value... } // f automatically falls from scope here, releasing the memory allocated to value.p }