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What is the skydiver's average velocity for the first 3 seconds?
Wiki User
∙ 14y ago
14.715 m/s.
This is worked out by knowing that gravity will accelerate a body at 9.81 (m/s)/s. The average velocity is the speed at 3s plus the speed at 0s divided by 2.
Speed at 0s = 0 x 9.81 = 0 m/s
Speed at 3s = 3 x 9.81 = 29.43 m/s
(29.43 + 0) / 2 = 14.715 m/s.
Wiki User
∙ 14y ago
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A ball thrown vertically upward returns to the starting point in 8 seconds.find its initial velocity.?
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
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What is the skydivers average velocity for the first 3 second?
14.715 m/s. This is worked out by knowing that gravity will accelerate a body at 9.81 (m/s)/s. The average velocity is the speed at 3s plus the speed at 0s divided by 2. Speed at 0s = 0 x 9.81 = 0 m/s Speed at 3s = 3 x 9.81 = 29.43 m/s (29.43 + 0) / 2 = 14.715 m/s.
True or false Skydivers spend the first several seconds of their jump in free fall?
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Do skydivers spend the first several seconds of their jump in freefall?
Yes, skydivers do spend the first several seconds of their jump in free fall. They do not usually open their parachutes until they are about 2,000 feet above the ground. Opening the parachute too soon might cause the parachutist go extremely way off course or result in an updraft that will cause injury.
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yes
Is it possible for the average velocity of an object to be zero during some interval even thought its average velocity for the first half of the interval is not zero explain and cite an example?
i think no
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A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
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