We'll assume you mean 2 seconds AFTER he's jumped from the plane. A good estimate would be 9.8m/s times 2 (9.8m/s/s times 2 seconds -- the standard value of the acceleration due to gravity). In two seconds, the velocity would be low enough that air resistance could probably be ignored for purposes of answering your homework. So try 19.6 m/s, unless your teacher gave your data on the air resistance of the sky diver.
Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.
"8 seconds" is not a velocity.
14.715 m/s. This is worked out by knowing that gravity will accelerate a body at 9.81 (m/s)/s. The average velocity is the speed at 3s plus the speed at 0s divided by 2. Speed at 0s = 0 x 9.81 = 0 m/s Speed at 3s = 3 x 9.81 = 29.43 m/s (29.43 + 0) / 2 = 14.715 m/s.
.13m
Two ways: If the change in velocity is the result of hitting something, use the Momentum Equation. If the change in velocity is the result of applying a force, use the Impulse Equation. You probably mean this equation, which is: FT = m(Vf - Vo) Or, An object of mass "m" will change from velocity "Vo" to velocity "Vf" if the force "F" is applied for "T" seconds.
187 miles per hour.
To calculate this, you divide the change in velocity, by the time.
Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.
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Neglecting air resistance his velocity after 1 second will be 9.81 m/sec or 32.2 ft/sec.
Velocity increases after 5 seconds
He will decelerate (meaning an acceleration in the direction opposite of current velocity) at a rate of (54 m/s - 4 m/s)/.75 seconds = 66.67 m/s2. This is about 6.8 Gs.
Velocity is derived by dividing displacement with time in seconds
The duration of The Skydivers is 1.25 hours.
The average velocity has two parts to it: The average speed and the average direction. The average speed is: (the distance you travel between 0 and 3 seconds) divided by (3). The average direction is: the direction from (the place where you started at 0 seconds) to (the place where you finished at 3 seconds).
Ignoring air resistance and using g = 9.81 ms-2, velocity = 20.38 ms-1.
The velocity = (location at 40 seconds - location at 20 seconds)/20 in the direction in which the object is moving.