Slope intercept form is written in the form y = mx + b, where b is the y-intercept when x = 0, and m is the slope of the line. Then, this equation 3x - 4y = 1 in changed to y = -3/4x + 1/4.
3x+4y = 8 4y = -3x+8 y = -3/4x+2 in slope intercrpt form It has a negative slope so the straight line goes 'downhill'
The parallel equation works out as: 4y = 3x+1 which can be expressed in the form of 3x-4y+1 = 0
3x - 4y = 1Subtract 3x from each side:-4y = -3x + 1Multiply each side by -1:4y = 3x - 1Divide each side by 4:y = 3/4 x - 1/4The graph is a straight line with [ slope = 3/4 ] and [ y-intercept = -1/4 ].
3x - 4y = 10-3x - 4y = 8 -> add line 1 to line 2 3x - 4y = 100x - 8y = 18 -> -8y = 18 -> y = -18/8 = -9/4 -> 3x - 4*(-9/4) = 10 -> 3x + 9 = 10 -> 3x = 1 -> x = 1/3
They are two regions of the Cartesian plane with the straight line 3x + 4y = 12 defining their boundary. That line is not part of either region.
3x-4y = 8 -4y = -3x+8 y = 3/4x-2 or y = 0.75x-2 which is the equivalent in slope intercept form
-3/4 if the question is 3x+4y
standard form is y = mx + b where m = slope 12 x+ 4y = 24 3x + y = 6 y = -3x + 6 slope is -3
4/3 First, get this into slope-intercept form (get y by itself). 3x+4y=12 -> Move 3x to the right by subtracting from both sides. -3x -3x 4y=12-3x -> get y alone by dividing everything by 4. 4y=-3x+12 ÷4 ÷4 ÷4 y=(-3/4)x+3 -> The slope is -3/4. To get the perpendicular line's slope you take the slope (-3/4) and flip it and switch the sign: negative becomes positive, 3/4 becomes 4/3.
-3x + 4y = 12∴ 4y = 3x + 12∴ y = 3x/4 + 3So this is a line with a slope of 3/4, an x-intercept of {0, 3} and a y-intercept of {-4, 0}
3x - 4y = -1
Lines parallel to the line would have the same slope, which is 3/4. (0.75) 3x-4y = 12 3x-12 = 4y y = 3/4 x - 3 The y-intercept is -3 and the slope is 3/4.