Solute and solvent are not adequate terms for the majority of alloys.
Solute and solvent are not adequate terms for the majority of alloys.
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Ocean water: the solvent is water, the solutes are chlorides of Na, Ca, K, Mg etc.Pepsi Cola: the solvent is water, the solutes are caramel, caffeine, sweeteners, sodium citrate, phosphoric acid etc.
A solute depresses the freezing point of a solution because the solute can not fit perfectly into the crystal lattice of the solid solvent. The normal crystal lattice is the lowest energy arrangement of the molecules or ions of the solid solvent. Therefore, the disordered lattice of a solvent freezing in the presence of a solute has at least slightly higher energy than the lattice of a solid pure solvent and requires at least a slightly lower temperature to solidify.
The ebullioscopic constant is a proportionality constant that relates the lowering of the vapor pressure of a solvent to the concentration of solute particles in the solution. It is specific to each solvent and is used in calculating the change in boiling point of a solvent when a nonvolatile solute is added. The formula for calculating the change in boiling point (∆Tb) is ∆Tb = i * K * m, where i is the van't Hoff factor, m is the molality of the solution, and K is the ebullioscopic constant.
Dissolution is the process of dissolving a solute in a solvent. It does not involve any chemical change. �Some elements are more mobile than others � �Most commonly promoted by acid � �KAlSi3O8 + H2O > Al2Si2O5(OH)4 + K+ + H4SiO4
1) Strong solute-solvent greater solubility while weak solute-solvent attractions equate to lesser solubility 2) Temperature (for gaz high temperature decrease solubility) 3) Pressure for solubility gaz in liquid 4) Polarity of solvent: Like dissolves like
It's not the ingredients in salt, but the presence of the salt itself. The salt holds the water in because of its attractive forces and blocking of the water throughout the mixture. Any soluble substance will affect the boiling and freezing points of any solvent based on how big the solute particles are, and the boiling/freezing pt constants, K, for the solvent.
√(40)=k√(10) Isolate k by dividing both sides by √(10) √(40)/√(10)=k √(40/10)=k √(4)=k k=2
Use a solvent which do not dissolve the solute. For example, if you want to determine the density of sugar, and sugar, as we all know, is soluble in water. So, instead of water we can substitute it with oil.
10-k=5
Well let's take an example that we have an a container with both oil and water in it these are inmiscible, know, let's say there is elemental iodine I2 in this container, iodine is nonpolar, so there will be more dissolved in the oil (an organic non polar solvent) than the water (a nonorganic polar solvernt). However, there will be a trace amount of iodine dissolved in the water. The distribution coefficient for this oil, we will say equals K. K=(concentration in mol/L of I2 in oil)/(concentration in mol/L of I2 in water) The distribution constant describes thr ration of iodine concentration in the organic layer to that in water.