2CsOH + H2SO4 = Cs2SO4 + 2H2O ... Ans
its easy :use the Periodic Table and the balancing equations for help.
If you realize SO4 has a valency of 2 and Cs has a valency of 1 so we need 2 Cs to balance SO4. We also know that water is a product as this is a neutralization equation(acid reacting with a base). Since we know that we put the equation as:-
CsOH + H2SO4 = Cs2SO4 + H2O
Now we see that there is 1 more atom of Cs on the right than on the left so we increase the CsOH to 2CsOH. Now the equation will look like this:-
2CsOH + H2SO4 =Cs2SO4 + H2O
Now we see there are more oxygen atoms and hydrogen atoms on the left than right so we make H2O to 2H2O. Now the reaction is balanced.
In order to recheck you can check whether the atoms of the elements on either side is the same.
That reaction is
2CsOH(aq)+H2SO4(aq)--->Cs2SO4(aq)+2H2O(l)
how will make solution for 0.005 h2so4
Fe2O3 + H2SO4
CsOH is a strong base
H2SO4+Hg
Pb + PbO2 + H2SO4 --> PbSO4 + H2O
ZnSO4+4CO=
how will make solution for 0.005 h2so4
Fe2O3 + H2SO4
CsOH is a strong base
H2SO4+Hg
Pb + PbO2 + H2SO4 --> PbSO4 + H2O
CsOH is a strong base
The answer is 1,2 mol.
Br2 + 2H2O + SO2 = H2SO4 + 2HBr
LiCl+H2SO4=LiHSO4+HCl
H2SO4 + ZnO => H2O + ZnSO4
h2c204+h2so4