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What is the speed of a 2.5-kilogram mass after it has fallen freely from rest through a distance of 12 meters?
Wiki User
∙ 13y ago
The best way to solve this is using conservation of energy: Potential Energy=mass*gravity*(change in height)=2.5*9.8*12=294 When you release the mass, it begins transferring it's potential energy into kinetic energy, so after your fall of 12 meters all of that potential energy is converted to kinetic. Kinetic Energy=(1/2)*mass*velocty^2
so
294=(1/2)*2.5*(v^2) A bit of algebra later: v=sqrt(294*2/2.5) v=15.336 m/s
But check my work because I could have messed up my math, but the logic is right.
Wiki User
∙ 15y ago
Wiki User
∙ 13y ago15
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