-0.76
Zn2+ + 2e- <--> Zno -0.7618 V
-0.76
-0.76
-0.76
Answer this question… Fe3+
silver reduced , gold oxidized
- .92 V
Zn(s)/Zn2+(aq)//Au+(aq)/Au(s)
Zn(s)--- Zn2+(aq)+2e-and Ni2+(aq)+e----Ni(s)
Zinc has a negative reduction potential (Eo = -0.76V) so it is favorable for zinc to be oxidized (the opposite of being reduced) under standard conditions: Zn --> Zn2+ + 2 e- Eo = +0.76V In sulfuric acid you primarily have three species present (not including the water): H+, HSO4-, and SO42-. Of these three, H+ has the highest reduction potential: 2 H+ + 2 e- --> H2 Eo = 0.00V So in the presence of H+ ions from sulfuric acid, zinc will oxide to form Zn2+: 2 H+ + Zn --> H2 + Zn2+ Eo = 0.00V + 0.76V = 0.76 V
-2.37 V (apex) Chace
Zn(s)/Zn2+(aq)//Au+(aq)/Au(s)