Answer this question… Fe3+
Fe3 is the least likely to be reduced because it has the highest oxidation state among the listed elements, making it less prone to gaining electrons and being reduced.
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The net ionic equation for iron II chloride (FeCl2) and copper (Cu) is: Fe2+ (aq) + Cu(s) → Fe(s) + Cu2+ (aq)
When your paper clip is made of (or coated with) more reactive metals than copper, like Fe, Zn or Sn, it might react with Cu2+ ions in your solution. Cu2+ + Fe(s) --> Cu(s) + Fe2+
When iron ions react with potassium permanganate, the iron ions are oxidized, and the potassium permanganate is reduced. The overall reaction results in the formation of iron(III) ions and manganese dioxide.
Fe3 is the least likely to be reduced because it has the highest oxidation state among the listed elements, making it less prone to gaining electrons and being reduced.
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Cu2+(aq) + 2e- → Cu(s) and Fe(s) → Fe2+(aq) + 2e-
Cu2+ e.g. CuS04 is blue in colour Fe2+ e.g. FeSO4 is green in colour Fe3+ e.g. Fe2O3 is brown in colourCorrect me if I'm wrong
The net ionic equation for iron II chloride (FeCl2) and copper (Cu) is: Fe2+ (aq) + Cu(s) → Fe(s) + Cu2+ (aq)
When your paper clip is made of (or coated with) more reactive metals than copper, like Fe, Zn or Sn, it might react with Cu2+ ions in your solution. Cu2+ + Fe(s) --> Cu(s) + Fe2+
When iron ions react with potassium permanganate, the iron ions are oxidized, and the potassium permanganate is reduced. The overall reaction results in the formation of iron(III) ions and manganese dioxide.
When an iron nail is dipped in copper sulfate solution, a displacement reaction occurs. The iron nail will displace the copper from the copper sulfate solution to form iron sulfate solution and copper metal deposits on the nail. This reaction is represented by the equation: Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s).
The reaction HgO -> Hg + O2 is a decomposition reaction, where HgO breaks down into its constituent elements mercury (Hg) and oxygen gas (O2).
molecular equation: CuSO4 (aq)+Fe (s) --> Cu(s) + FeSO4(aq) net ionic equation: Cu2+(aq) + Fe2+ (s) --> Cu2+(s) + Fe2+(aq) spectator ion: Sulfate Ion (SO42-)
The Fe2 ion has 4 unpaired electrons.