There is ClO2 and ClO2^-. For the chlorite anion (ClO2^-) the Cl will have 10 electrons and will violate the octet rule. For ClO2, all elements will have 8 electrons.
ClO2 → Cl + O2
In the Chlorite ion (ClO2-) chlorine's oxidation state is 3+ while oxygen's oxidation state is 2-
Chlorite ( ClO2- ) is the base anion of chlorous acid: HClO2, the Oxidation number (or state) of Cl in this compoud is +3 according to this:oxidation state−1+1+3+5+7anion namedchloridehypochloritechloritechlorateperchlorateformulaCl-ClO−ClO2−ClO3−ClO4−
First , its NaOCl, with a lowercase L, not an i. There are 12 atoms in 4 formula units of NaOCl.
0.0362 x 1911.9 g = 69.2 g NaOCl (to 3 significant figures based on 0.0362).
3.62 percent by mass means that there are 3.62 g NaOCl per every 100 g of solution. So, to find grams in 1911.9 g solution, just multiply ...3.62 g NaOCl/100 g soln x 1911.9 g soln = 69.2 g NaOCl
by reacting the brome in the the sodium chloride: Br + NaCl----- BrNa + cL---------cl+naocl= naocl
acetone
Formula: NaOCl
No - bleach is NaOCl
No, KClO2 will dissociate in water: KClO2 → K+ + ClO2- The ClO2- ion will remove protons from the solution (ClO2- + H2O → HClO2 + OH-) and leave hydroxide ions, making the solution basic.