+6
2x-12-2=-2
2x=12
x=6
This is because there are 1 peroxy bond in S2O82- because of which 2 of the 8 oxygen atoms have -1 oxidation state other 6 Oxygen atoms have -2
-2, the sum of the oxidation numbers should equal the charge on an atom
The oxidation numbers of the elements in a chemical formula, some of which will be positive and others of which will be negative, when multiplied by the numbers of atoms with each oxidation number, must produce products that add to a net result of zero.
Oxidation numbers
-3. The sum of oxidation numbers of the atoms in all polyatomic ion is the net charge - its part of the definition of oxidation number.
Oxidation numbers are defined for atoms, not molecules such as N2. The oxidation number of both atoms in a divalent elemental molecule is specified to be 0, as is the oxidation number of an atom of an element for which one atom constitutes a molecular unit.
+7 for Mn -2 for each O
The oxidation numbers for the atoms in the ionic compound KCl are K+1 and Cl-1.
oxidation numbers
The oxidation numbers of the elements in a chemical formula, some of which will be positive and others of which will be negative, when multiplied by the numbers of atoms with each oxidation number, must produce products that add to a net result of zero.
Oxidation numbers
In a neutral compound, the sum of the oxidation numbers of the atoms in the compound is zero.
-3. The sum of oxidation numbers of the atoms in all polyatomic ion is the net charge - its part of the definition of oxidation number.
Oxidation numbers are defined for atoms, not molecules such as N2. The oxidation number of both atoms in a divalent elemental molecule is specified to be 0, as is the oxidation number of an atom of an element for which one atom constitutes a molecular unit.
+7 for Mn -2 for each O
The oxidation numbers for the atoms in magnesium oxide are: Mg+2 and O-2.
the charge on that ion
Assuming you mean what is the oxidation number of each atom in the compound C3H8O? Oxidation rules state the the sum of all oxidation numbers in a neutral molecule equals 0. 1. O = -2 2. H = +1 3. C = -2 These numbers are derived from... (-2) + (+1 x 8) + (-2 x 3) = 0
Nitrogen has the oxidation number of +IV and oxygen atoms mark as -II.