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+7 for Mn

-2 for each O

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Q: What are the oxidation numbers of the atoms in the MnO4- ion?
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What is the sum of the oxidation numbers in the phosphate ion?

-3. The sum of oxidation numbers of the atoms in all polyatomic ion is the net charge - its part of the definition of oxidation number.


In a polyatomic ion the algebraic sum of the oxidation numbers of all atoms is equal to?

the charge on that ion


In a polyatomic ion the algebraic sum of all the oxidation numbers of all atoms equal to?

the charge on that ion


What is the oxidation number of MN in 2MnO4-?

I assume you mean the oxidation number of Mn in the permanganate ion , MnO4- The sum of the oxidation numbers is the charge on a polyatomic ion so Mn has an oxidation number of +7 as each O is assigned -2.


Why must oxidation numbers be assigned to the elements before writing a chemical formula?

The oxidation numbers of the elements in a chemical formula, some of which will be positive and others of which will be negative, when multiplied by the numbers of atoms with each oxidation number, must produce products that add to a net result of zero.


What is the permanganate ion composed of?

MnO4- is the chemical formula for permanganate. The charge is generally -1.


What is the oxidation state of cl in clo2?

This is a gas compound. Chlorine shows +4 as the oxidation number.


What is the oxidation number in MnO4?

K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7


What determines the oxidation number?

The oxidation number determines how much an element is oxidated, so the oxidation number of...1. elements is always 0.2. of simple ions is always the charge, e.g. in Cu2+ the oxidation number of copper is +2.3. hydrogen is usually +1, oxygen usually -2, alkali metals +1, etc.In molecules without a charge, the sum of the oxidation numbers has to be 0. This way you can calculate the oxidation number of its compounds. For example in KMnO4, the oxidation number of oxygen is -2, of K is +1, so if the sum is zero then the oxidation number of Mn has to be +7.In complex ions (OH-, MnO4-, ...) the sum of the oxidation numbers has to be the charge of the ion. (so in OH- and MnO4- it's -1).


How do you calculate the the oxidation number of mn in k2mno4?

First O has an oxidation number of -2; K will an oxidation number of +1 as it is an alkali metal. Therfore the Mn is +6. note that while the manganate ion exists, the question may relate to the permanganate ion MnO4-, so KMnO4, where Mn has oxidation number of +7


Is an oxidation number the same as the type of ion formed?

The overall oxidation number of an ion is indeed the charge. Na+, sodium is +1 ON, Cl-, chlorine is -1 ON. For a polyatomic ion the charge is the sum of the oxidation numbers of the consituent atoms. For example NH4+ ; N is -3, H is +1 so overall ON is +1 same as the charge.


What is the sum of the oxidation numbers of all the atoms in the peroxydisulfate ion S2O82?

+6 2x-12-2=-2 2x=12 x=6 This is because there are 1 peroxy bond in S2O82- because of which 2 of the 8 oxygen atoms have -1 oxidation state other 6 Oxygen atoms have -2