CBr4 , this is the correct formula for carbon-tetra-bromide
Carbon Tetrabromide
152
1
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
CBr4
325 g of CBr4 have 5,9.10e23 molecules.
Yes
No. CBr4 is nonpolar and H2O is polar. Both do not mix.
No, it is not.
No CBr4 is covalent.
CBr4
CBr4
Carbon Tetrabromide
Carbon Tetrabromide - or tetrabromomethane
152
1
Covalent ~