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How many molecules are in 334 g CBr4?
To calculate the number of molecules in 334 g of CBr4, you need to first convert the mass to moles using the molar mass of CBr4 (331.6 g/mol). Once you have the moles, you can then use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules in 334 g of CBr4.
How many molecules are in 366g CBr4?
To find the number of molecules in 366g of CBr4, first calculate the molar mass of CBr4 which is 331.63 g/mol. Next, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert grams to molecules. Divide the given mass by the molar mass and then multiply by Avogadro's number to find the number of molecules.
How much viscosity in cf4 ccl4 and cbr4?
CF4 has the lowest viscosity, followed by CCl4, and then CBr4. This is because viscosity is generally higher for heavier molecules due to stronger intermolecular forces that inhibit molecular motion.
How many covalent bonds are peresent in CBr4?
There are four covalent bonds present in CBr4. Each carbon atom forms a single covalent bond with each of the four bromine atoms.
Will CBr4 and H2O form homogeneous solutions when combined?
No, CBr4 and H2O will not form a homogeneous solution. CBr4 is a nonpolar compound, while H2O is polar. Due to the significant difference in polarity, they will not mix evenly to form a homogeneous solution.
How many molecules are in 334 g CBr4?
To calculate the number of molecules in 334 g of CBr4, you need to first convert the mass to moles using the molar mass of CBr4 (331.6 g/mol). Once you have the moles, you can then use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules in 334 g of CBr4.
How many molecules are in 393g of CBr4?
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
How many molecules are in 366g CBr4?
To find the number of molecules in 366g of CBr4, first calculate the molar mass of CBr4 which is 331.63 g/mol. Next, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert grams to molecules. Divide the given mass by the molar mass and then multiply by Avogadro's number to find the number of molecules.
What is 60 percent of 325g?
60% of 325g= 60% * 325= 0.6 * 325= 195g
How many carbon atoms are in CBr4?
1
What is the symbol for CBr4?
CBr4 , this is the correct formula for carbon-tetra-bromide
How much viscosity in cf4 ccl4 and cbr4?
CF4 has the lowest viscosity, followed by CCl4, and then CBr4. This is because viscosity is generally higher for heavier molecules due to stronger intermolecular forces that inhibit molecular motion.
How many covalent bonds are peresent in CBr4?
There are four covalent bonds present in CBr4. Each carbon atom forms a single covalent bond with each of the four bromine atoms.
Will CBr4 and H2O form homogeneous solutions when combined?
No, CBr4 and H2O will not form a homogeneous solution. CBr4 is a nonpolar compound, while H2O is polar. Due to the significant difference in polarity, they will not mix evenly to form a homogeneous solution.
Is CBr4 metal or non-metal?
Yes
How many milliliter are 325g?
This cannot be sensibly answered. Milliliters (mL or ml) is a measure of volume, grams is a measure of weight or mass.
Formula for carbon tetrabromide?
CBr4
