334 g x 1 mol/331.6 g x 6.02x10^23 molecules/mole = answer
To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.
To find the number of molecules in 366g of CBr4, first calculate the molar mass of CBr4 which is 331.63 g/mol. Next, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert grams to molecules. Divide the given mass by the molar mass and then multiply by Avogadro's number to find the number of molecules.
The amount of energy required to melt ice is given by the formula Q = m * L, where Q is the energy in joules, m is the mass in grams, and L is the heat of fusion for ice (334 J/g). Plugging in the values, we find that it would take 12.8 g * 334 J/g = 4288 joules to melt 12.8 g of ice at 0°C.
There are 3.34 x 10^22 molecules of H2O in 1.0 g of water.
4.3 g * 1 mol/18.02 g * 6.03 kJ/mol
To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
To find the number of molecules in 366g of CBr4, first calculate the molar mass of CBr4 which is 331.63 g/mol. Next, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert grams to molecules. Divide the given mass by the molar mass and then multiply by Avogadro's number to find the number of molecules.
The heat required to melt ice is called the heat of fusion, which is 334 J/g. To melt 500g of ice, you would need 334 J/g x 500g = 167000 joules of heat.
The heat needed to freeze 100 g of water is 334 J/g. So, for 100 g, the total heat needed would be 334 J/g * 100 g = 33,400 J.
22.0 g of silver chloride contain 0,918.10e23 molecules.
26.3 g of calcium hydroxide contain 2,054 molecules.
The amount of energy required to melt ice is given by the formula Q = m * L, where Q is the energy in joules, m is the mass in grams, and L is the heat of fusion for ice (334 J/g). Plugging in the values, we find that it would take 12.8 g * 334 J/g = 4288 joules to melt 12.8 g of ice at 0°C.
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
2
The answer is 1,57.10e27 molecules.
1,4.10e23 molecules