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334 g x 1 mol/331.6 g x 6.02x10^23 molecules/mole = answer

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How many molecules are in 325g of CBr4?

To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.


How many molecules are in 393g of CBr4?

The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23


How many molecules are in 366g CBr4?

To find the number of molecules in 366g of CBr4, first calculate the molar mass of CBr4 which is 331.63 g/mol. Next, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert grams to molecules. Divide the given mass by the molar mass and then multiply by Avogadro's number to find the number of molecules.


How many joules of heat are necessary to melt 500g of ice at its freezing point?

The heat required to melt ice is called the heat of fusion, which is 334 J/g. To melt 500g of ice, you would need 334 J/g x 500g = 167000 joules of heat.


How much heat is needed to freeze 100 g of water?

The heat needed to freeze 100 g of water is 334 J/g. So, for 100 g, the total heat needed would be 334 J/g * 100 g = 33,400 J.


How many molecules are there in 22.0 g of silver chloride?

22.0 g of silver chloride contain 0,918.10e23 molecules.


How many molecules are in 26.3 g of calcium hydroxide?

26.3 g of calcium hydroxide contain 2,054 molecules.


How many joules are required to melt 12.8 g of ice at 0 and degC?

The amount of energy required to melt ice is given by the formula Q = m * L, where Q is the energy in joules, m is the mass in grams, and L is the heat of fusion for ice (334 J/g). Plugging in the values, we find that it would take 12.8 g * 334 J/g = 4288 joules to melt 12.8 g of ice at 0°C.


How many molecules are in 32 g of SO2?

32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules


How many molecules will there be in 1.0 g of ATP?

2


How many molecules (not moles) of NH3 are produced from 1.57104 g of H2?

The answer is 1,57.10e27 molecules.


How many O2 molecules are needed to react with 7.45 g of S?

1,4.10e23 molecules