The heat needed to freeze 100 g of water is 334 J/g. So, for 100 g, the total heat needed would be 334 J/g * 100 g = 33,400 J.
41,800
No heat (energy) is required to freeze water (from liquid to solid). Freezing RELEASES energy (heat), as it is an exothermic event. If you want to know how much energy is release, you need to know the heat of fusion for water, and then multiply that by the mass of water being frozen.
The necessary heat is 9,22 joules.
The amount of heat removed during the process of steam condensing and then freezing into ice is calculated by adding the heat required to condense the steam and the heat required to freeze the resulting water. This is determined using the specific heat capacity and latent heat of vaporization/condensation for water.
1oo calories for 1 g
The specific heat of water determines how much energy is needed to heat water.
The needed heat is 2 258 kJ.
41,800
It depends on how much it needs to be cooled down, or transferred. The more heat there is the more coolant (water) is needed.
No heat (energy) is required to freeze water (from liquid to solid). Freezing RELEASES energy (heat), as it is an exothermic event. If you want to know how much energy is release, you need to know the heat of fusion for water, and then multiply that by the mass of water being frozen.
A calorie is the amount of energy needed to heat 1 gram of water by 1 degree Celsius. So you can't burn a calorie.
The necessary heat is 9,22 joules.
The heat needed can be calculated using the formula: Q = mc∆T, where Q is the heat, m is the mass of water, c is the specific heat capacity of water (4186 J/kg°C), and ∆T is the change in temperature. Plug in the values to find the heat needed.
It would depend on the temperature of the water, or average kinetic energy. (KE) However, what you may be looking for is how much heat is needed to raise the KE, or temperature, of water. 4.184 kilojoules per gram is the heat required to raise the temperature of water 1 degree Celsius.
To calculate the heat needed to change ice to water, we use the specific heat capacities and latent heat of fusion. First, calculate the heat needed to raise the temperature of 565 g of ice from -13°C to 0°C using specific heat capacity of ice. Then, calculate the heat needed to melt the ice at 0°C to water at 0°C using the latent heat of fusion for ice. Finally, calculate the heat needed to raise the temperature of water from 0°C to 20°C using the specific heat capacity of water. Add these three values together to find the total heat required.
2,641,760J...
A calorie of energy (NOT to be confused with a Calorie, they are different so watch the caps) is the amount necessary to heat 1 gram of water 1oC, so 30 calories are needed to heat 30 g of water 1 degree. To heat it 70oC would take 2100 calories (or 2.1 Calories) of energy.