2,641,760J...
If its in Celsius then another 13 degrees are needed because water boils at 100 degrees Celsius
The boiling point of water is 100 degrees Celsius and the melting point of water is 0 degrees Celsius
To raise the temperature of 1 liter of water by 1 degree Celsius, it requires 1 kilocalorie. Therefore, to burn 330 kilocalories and heat cold water from 4 degrees Celsius to 37 degrees Celsius, you would need to drink 33 liters of cold water.
The temperature in Celsius at which water boils is 100 degrees.
The enthalpy change for converting 1 mol of ice at -50 degrees Celsius to water at 70 degrees Celsius is the sum of the enthalpy changes for the following processes: heating ice from -50 degrees Celsius to 0 degrees Celsius (heat of fusion), melting ice at 0 degrees Celsius, and heating water from 0 degrees Celsius to 70 degrees Celsius (specific heat of water).
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
To convert 4 kg of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to calculate the heat required to raise the temperature of ice to 0 degrees Celsius, melt the ice to water at 0 degrees Celsius, raise the temperature of water to 100 degrees Celsius, and then convert water to steam at 100 degrees Celsius. The total amount of heat needed can be calculated using the specific heat capacities and latent heats of fusion and vaporization of water.
True. A calorie is defined as the amount of heat energy needed to raise the temperature of 1 gram of water by 1 degree Celsius.
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
Q=mcΔT Q=14 x 4200 x 21.6 Q=1270080J
It takes 6 SI calories to raise one liter of water by 6 degrees Celsius.
Yes, one calorie is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree Celsius.
The specific heat capacity of water is 4.18 J/g°C, which means it takes 4.18 Joules of energy to raise 1 gram of water by 1 degree Celsius. To raise the temperature of 8.1 g of water by 20 degrees Celsius, you would need 8.1 g * 20°C * 4.18 J/g°C = 676.56 Joules of energy.
If its in Celsius then another 13 degrees are needed because water boils at 100 degrees Celsius
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
The amount of heat necessary to raise 1 gram of a substance by 1 degree Celsius is known as?
Heating of water=m x s x delta T,where m is the mass ,s is the specific heat of water(1 cal/gm)=5x1x(50-25) =125 cal