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32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules

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What is the mass percent of oxygon (O) in SO2?

The molar mass of SO2 is 64.06 g/mol. Oxygen contributes 32 g/mol to this molar mass, so the mass percent of oxygen in SO2 is (32 g/mol / 64.06 g/mol) x 100, which is approximately 50%.


What is the mass percent of oxygen in SO2?

The molar mass of SO2 is 64.07 g/mol. Since oxygen has a molar mass of 16 g/mol and there are 2 oxygen atoms in SO2, the total mass of oxygen in SO2 is 32 g. Therefore, the mass percent of oxygen in SO2 is 32/64.07 * 100% = 50.05%.


What is the mass percent in oxygen SO2?

I assume you mean mass of oxygen % in SO2. This is calculated by finding the molecular weight of S and O (32 and 16 respectively) As there are 2 oxygens, 16 is multiplied by 2, = 32. put 32 over the total, = 32/64. Which equals 50%


How many moles are in 3.82 g of SO2?

To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.


What is the number of molecules in 8 g of oxygen gas?

1) 7 g co 2)16 g so2 3)11 g co2


How many moles of SO2 are present in 250.0 g?

Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.


What is the mass of 0.75 mole of so2?

The molar mass of SO2 (sulfur dioxide) is approximately 64.06 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles (0.75) by the molar mass (64.06 g/mol) to get the mass of 0.75 moles of SO2, which is 48.045 grams.


What is the equilibrium constant for the reaction so2 (g) no2 (g) so3 (g) no (g)?

SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.


What is the total mass and grams of 0.75 mole of SO2?

The molar mass of SO2 is approximately 64.07 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles by the molar mass: 0.75 moles x 64.07 g/mol = 48.05 grams Therefore, the total mass of 0.75 moles of SO2 is 48.05 grams.


How many molecules of sulfur dioxide are present in 72 g of the substance?

To determine the number of molecules of sulfur dioxide in 72 g of the substance, we first need to calculate the number of moles of sulfur dioxide present. The molar mass of sulfur dioxide (SO2) is approximately 64 g/mol. Therefore, 72 g of sulfur dioxide is equal to 72 g / 64 g/mol = 1.125 moles. Next, we use Avogadro's number, which is 6.022 x 10^23 molecules/mol, to convert moles to molecules. Therefore, there are approximately 6.78 x 10^23 molecules of sulfur dioxide in 72 g of the substance.


How many moles are present in 2.56g of So2?

To find the number of moles in 2.56g of SO2, you first need to calculate the molar mass of SO2 (64.07 g/mol). Then, divide the given mass (2.56g) by the molar mass to get the number of moles. In this case, 2.56g of SO2 is equal to 0.04 moles.


How many grams of sulfur must be burned to give 100.0 g of SO2?

To calculate the number of grams of sulfur burned to produce 100.0 g of SO2, we first need to find the molar mass of SO2. The molar mass of SO2 is 64.1 g/mol. Since there is one sulfur atom in each molecule of SO2, the molar mass of sulfur is 32.1 g/mol. Therefore, 32.1 grams of sulfur must be burned to produce 100.0 g of SO2.