0
#1 Remember the moles equation , which is
moles = mass(g) /Mr
#2 Mr is the relative molecular mass of the given substance.
For SO2 it is'
1 x s = 1 x 32 = 32
2 O = 2 x 16 = 32
32 + 32 = 64
Hence substituting
moles(SO2) = 2.56g / 64 = moles = 0.04 moles
NB When writing chemical formula, single letter symbols are ALWAYS a CAPITAL letter. Hence sulphur is 'S' and oxygen is 'O'. NOT 'o'
A double letter symbol is written as , 1st leter is a capital letter and the second letter is small / lower case. e.g. Sodium is 'Na'.
lenpollock
Wiki User
∙ 11y ago64 g of SO2 = 1 mole
2.56 g = (1 * 2.56) / 64 = 0.04 mole
Add your answer:
Earn +20 pts
How many moles are present in 128 grams of sulphur dioxide?
Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2
How many moles of SO2 are present in 250.0 g?
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
What is the limiting reagent when 3.1 moles of so2 react with 2.7 moles of o2?
2SO2 +O2 -----> 2SO3 so 3.1 moles of SO2 would require 1.55 moles of O2 so since there are 2.7 moles of O2 present and thus in excess, the SO2 is the limiting reagent.
How many moles of C are needed to react with 0.490mole SO2?
How many moles of C are needed to react with 0.490 mole SO2?
How many moles of CS2 form when 3 moles of SO2 reacts?
14
How many moles of SO2 is present in 0.45 grams of sulfur dioxide?
1 mole SO2 = 64.064g SO2 0.45g SO2 x 1mol SO2/64.064g SO2 = 0.0070 mole SO2
How many moles are present in 128 grams of sulphur dioxide?
Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2
How many moles of SO2 are present in 250.0 g?
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
What is the limiting reagent when 3.1 moles of so2 react with 2.7 moles of o2?
2SO2 +O2 -----> 2SO3 so 3.1 moles of SO2 would require 1.55 moles of O2 so since there are 2.7 moles of O2 present and thus in excess, the SO2 is the limiting reagent.
How many moles of C are needed to react with 0.490mole SO2?
How many moles of C are needed to react with 0.490 mole SO2?
How many moles of CS2 form when 3 moles of SO2 reacts?
14
How many moles of sulfur trioxide are formed from 3 moles of sulfur dioxide?
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
How many SO2 molecules are in 1.75 mol of SO2?
1.75 moles SO2 x 6.02x10^23 molecules SO2/mole SO2 = 1.05x10^24 molecules
How many molecules are present in 2.5 moles of SO2?
M means molarity, with units moles/Liter. Using this information, we use dimensional analysis: 2.5mL x (1L/1000mL) x (9mol/1L) = 0.0225mol
How many gram-moles in 320 grams of SO2?
5
How many moles of sulfur must be burned to give 0.567 moles of so2?
Cock and booty ball
How many grams are in 0.75 moles of SO2?
.75 moles times 64 grams/mols = 48 grams
