#1 Remember the moles equation , which is
moles = mass(g) /Mr
#2 Mr is the relative molecular mass of the given substance.
For SO2 it is'
1 x s = 1 x 32 = 32
2 O = 2 x 16 = 32
32 + 32 = 64
Hence substituting
moles(SO2) = 2.56g / 64 = moles = 0.04 moles
NB When writing chemical formula, single letter symbols are ALWAYS a CAPITAL letter. Hence sulphur is 'S' and oxygen is 'O'. NOT 'o'
A double letter symbol is written as , 1st leter is a capital letter and the second letter is small / lower case. e.g. Sodium is 'Na'.
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
How many moles of C are needed to react with 0.490 mole SO2?
To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.
To find the number of moles in 128 grams of sulfur dioxide, divide the given mass by the molar mass of SO2. The molar mass of SO2 is 32.07 g/mol (sulfur) + 2*(16.00 g/mol) (2 oxygen atoms) = 64.07 g/mol. Thus, there are 2 moles of SO2 in 128 grams.
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
How many moles of C are needed to react with 0.490 mole SO2?
To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.
To find the number of moles in 128 grams of sulfur dioxide, divide the given mass by the molar mass of SO2. The molar mass of SO2 is 32.07 g/mol (sulfur) + 2*(16.00 g/mol) (2 oxygen atoms) = 64.07 g/mol. Thus, there are 2 moles of SO2 in 128 grams.
Since oxygen is diatomic it requires 2 moles of oxygen.
1 mole of sulfur reacts with 2 moles of oxygen to produce 1 mole of SO2. Therefore, to produce 0.567 moles of SO2, you would need to burn 0.2835 moles of sulfur.
Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.
To determine the number of gram-moles in 320 grams of SO2, you first need to find the molar mass of SO2, which is 64.07 g/mol. Then you divide the given mass (320 g) by the molar mass to get the number of moles. Therefore, 320 grams of SO2 is equivalent to 5 moles.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The balanced chemical equation for the reaction between carbon (C) and sulfur dioxide (SO2) is C + 2SO2 -> CS2 + 2O2. From the equation, 1 mole of C reacts with 2 moles of SO2. Therefore, you would need 0.255 moles of C to react with 0.510 moles of SO2.