-67 degree Celsius = 206.15 kelvin.
200.
V1/T1 = V2/T2 Where temperature must be in Kelvins 67C + 273 = 340 K So 140/340 = 50/T2 Find T2 340/140(50) = T2 T2 = 121 K or -152C
It is the equivalent temperature of this in degrees Celsius.K = C + 273 (approx).
Beta Aquarii has a temperature of 5,700 Kelvins equal to 9800.33° F or 5426.85° C.
I'm not sure what the temperature is but i do know that its orbit isn't far behind earth so there isn't much of a difference. Edit : Neptune is along way from Earth and the temperature is much lower. The average temperature at the surface is about minus 220 degrees Celsius.
why dont people give good, simple answers?? its not that hard!! trying to do a project here!
Add 273.15 to the number of Celsius degrees to get the same temperature in Kelvins.
270.15K = -3C
-34 ºC = 239 K
This temperature is 239 K.
Add 273.15 to -34 = 239.15 Kelvin
-34 deg C = 239.15 K
Answer: -34 ºC = 239 K
Answer: -34 ºC = 239 K
In the ideal gas equation the temperature is in kelvins.
51 degrees Celsius = 324.15 kelvin[K] = [°C] + 273.15
32 deg F, 0 deg C or 273 K.
V1/T1 = V2/T2 Where temperature must be in Kelvins 67C + 273 = 340 K So 140/340 = 50/T2 Find T2 340/140(50) = T2 T2 = 121 K or -152C