It is the supply voltage divided by the rotor resistance including the resistance of the brushes.
Copper loss means the loss due to the resistance of conductor of any device. Core loss means the loss due to eddy current and hysterisis of flux. So the total loss of a transformer menas copper loss+core loss. Therefore just knowing the core loss the copper loss can not be deduced. These are being two different and not interrelated losses the value of one of them will not make way to find the other. I hope the answer is clear enough otherwise please write again
Copper loss electrons.
Copper Loss at 75 C = Copper Loss at Ambient Temperature C * (310/(235+Ambient Temperature C))
Iron loss it includes the core loss is partically the same at all loads and copper loss the value of cu loss is found from short circuit test
stray loss copper loss
Cu loss means I^2*R loss so it depends on R and I.If we make wire more resistive it means it will increase the value of R so copper loss will be increase.So to concentrate on wire size we can vary the R value and can protect the copper loss.So it is called variable loss.
Iron Loss Copper Loss Frictional loss
Copper loss varies with the load.
Copper loss electrons.
100 is to 800 as 75 is to X. Cross multiply, 100 x X and 800 x 75, 100X = 60000. To get rid of the 100 divide it into both sides of the equation. X = 600. If the copper loss is linear, at 75 percent the copper loss will be 600 watts.
Yes.
Maximum efficiency of a power transformer occurs when copper loss equals to iron losses. Decrease in current does not result in increase in efficiency unless the copper loss was more than iron loss and the decreased current made the copper loss is reduced and became equal to iron loss at some point.