Exactly the same as whatever it was before firing. If the loaded gun was not moving
before the trigger was pulled, then the total momentum of the gun and bullet after
firing add up to zero.
zero, same as it was before firing
If the gun is stationary before the shot, then the momentum of the gun and the momentum of the bullet are equal and opposite after the shot.
In an isolated system the total momentum of a system remains conserved. For example If you fire a bullet from Gun , bullet go forward with some linear momentum and in order to conserve the linear momentum the gun recoils
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A bullet fired from a gun
In the recoil? This follows from conservation of momentum. Actually, the momentum of the gun will be exactly opposite - or the negative - of the bullet's momentum. It can also be derived from Newton's Second and Third Laws.
Momentum = mass x velocity A bullet has a high momentum because its velocity is really high.
Because linear momentum is conserved. Before the shot, the momentum of (gun + bullet) is zero, so it has to be zero after the shot. The bullet gains forward momentum when fired, so the gun must gain reverse momentum in order to maintain the zero sum.
In an isolated system the total momentum of a system remains conserved. For example If you fire a bullet from Gun , bullet go forward with some linear momentum and in order to conserve the linear momentum the gun recoils
This is conservation of momentum. You have the hot gases from the explosive charge along with the bullet moving out the barrel, away from the person. Momentum is mass times velocity. While the mass of the bullet and gases are small, the velocity is very high. So nothing was moving before the trigger was pulled, so net momentum is zero. After the trigger is pulled, the momentum is still net zero. Any momentum away from the gunner will have an equal momentum (the gun recoiling) toward him. Since the gun has much more mass than the bullet, the velocity is much less.
Momentum before = momentum after. Since there was no movement before, momentum before = 0 If you think of the bullet as forward/positive momentum and the gun as backward/negative momentum then the momentum of the bullet plus the momentum of the gun =0 and therefore the momentum of the bullet = the momentum if the gun. momentum = mass x velocity P=m/v 20gx150m/s = 2000g (2kg) x velocity 3000 = 2000v 3000 / 2000 = v v = 1.5m/s
It is known as the Velocity (speed).
You compare the rifling marks on the bullet to the rifling in the barrel. You can also compare the firing pin mark on the primer to the firing pin on the gun.