A bullet fired from a gun
Because linear momentum is conserved. Before the shot, the momentum of (gun + bullet) is zero, so it has to be zero after the shot. The bullet gains forward momentum when fired, so the gun must gain reverse momentum in order to maintain the zero sum.
The law that says every action has an equal and oppsite reaction: the momentum of the bullet is balanced by the equal momentum of the gun (and shooter) in the opposite direction - the recoil.
You can use conservation of momentum to solve this. Just multiply momentum (= mass x speed) for the bullet, and assume that the change in (mass x speed) for the gun must be the same.
The idea is to use conservation of momentum. The momentum before the shot is fired is assumed to be zero, so write an equation that states that the momentum after the shot is zero, and solve it. The total momentum, of course, is the sum of the momentum of the two parts; for each part, the momentum is mass x velocity.
A bullet fired from a gun
Momentum = mass x velocity A bullet has a high momentum because its velocity is really high.
Because linear momentum is conserved. Before the shot, the momentum of (gun + bullet) is zero, so it has to be zero after the shot. The bullet gains forward momentum when fired, so the gun must gain reverse momentum in order to maintain the zero sum.
The law that says every action has an equal and oppsite reaction: the momentum of the bullet is balanced by the equal momentum of the gun (and shooter) in the opposite direction - the recoil.
If the gun is stationary before the shot, then the momentum of the gun and the momentum of the bullet are equal and opposite after the shot.
Momentum before = momentum after. Since there was no movement before, momentum before = 0 If you think of the bullet as forward/positive momentum and the gun as backward/negative momentum then the momentum of the bullet plus the momentum of the gun =0 and therefore the momentum of the bullet = the momentum if the gun. momentum = mass x velocity P=m/v 20gx150m/s = 2000g (2kg) x velocity 3000 = 2000v 3000 / 2000 = v v = 1.5m/s
You can use conservation of momentum to solve this. Just multiply momentum (= mass x speed) for the bullet, and assume that the change in (mass x speed) for the gun must be the same.
The idea is to use conservation of momentum. The momentum before the shot is fired is assumed to be zero, so write an equation that states that the momentum after the shot is zero, and solve it. The total momentum, of course, is the sum of the momentum of the two parts; for each part, the momentum is mass x velocity.
Speed of recoil of the gun = change in momentum/mass of the bullet = 5 x 10-3 x 800/5 msec-1 = 0.8 msec-1
In the recoil? This follows from conservation of momentum. Actually, the momentum of the gun will be exactly opposite - or the negative - of the bullet's momentum. It can also be derived from Newton's Second and Third Laws.
The bullet fired from a gun has greater horizontal acceleration. For vertical acceleration, they are both the same.
When a bullet is fired from a rifle, a chemical reaction in the gunpowder ignites, rapidly expanding gases build up pressure, and the bullet is propelled out of the barrel at high speed. The rifling in the barrel causes the bullet to spin, improving accuracy and stability. Gravity will eventually cause the bullet to drop due to gravity and air resistance.