0
What else can I help you with?
A 5 g bullet is fired from a 5000g gun If the bullet leaves the gun going 800MS with what speed does the gun recoil?
Using the principle of conservation of momentum, we can calculate that the gun will recoil at 0.08 m/s in the opposite direction of the bullet. The total momentum of the gun and bullet before firing is equal to the total momentum after firing.
When a 60g bullet fired from 5kg gun leaves with a speed of 500ms. Find the velocity with which the gun recoils?
By conservation of momentum, the momentum of the gun and bullet system before firing must equal the total momentum after firing. Therefore, the velocity at which the gun recoils can be calculated by using the equation: (mass of bullet * velocity of bullet)/mass of gun = velocity of gun. Substituting the values given: (0.06 kg * 500 m/s) / 5 kg = 6 m/s.
What are some examples of concervation of momentum?
Collisions between billiard balls where the total momentum before the collision is equal to the total momentum after. Recoil of a gun when a bullet is fired, where the forward momentum of the bullet is equal and opposite to the backward momentum of the gun. Ice skaters pushing off each other in opposite directions, resulting in a conservation of momentum system.
A 5g bullet is fired from a 500g if the bullet leaves the gun going 800ms with what speed does it recoil?
Using the principle of conservation of momentum, the momentum of the bullet before the gunshot is equal to the momentum of the bullet and gun after the shot. Calculating the recoil velocity using this principle shows that the gun will recoil at 1.6 m/s in the opposite direction.
What is the total momentum of cannon and shell before and after firing?
Before the cannon is fired, the momentum is zero. So, after firing, the momentum must still be zero. The momentum of the shell is equal and opposite to that of the cannon, because there is an action and an equal reaction force. Since the momentum difference must be equal: (mv)cannon = (mv)shell Thus, (mv)c - (mv)s = 0 A simple way of looking at it is this is: If the shell is 100 times lighter than the cannon then the shell will move off 100 times faster than the cannon recoils. Remember that, in explosions, the lighter portion moves off faster than the heavier one.
What is the total momentum of the bullet and the gun after firing?
Exactly the same as whatever it was before firing. If the loaded gun was not movingbefore the trigger was pulled, then the total momentum of the gun and bullet afterfiring add up to zero.
What is the recoil velocity of the pistol when a bullet of mass 200g is fired with a velocity 30m per second from a pistol of mass 100kg?
Use conservation of linear momentum. Before firing the bullet the total momentum was zero (assuming you were not moving), therefore, after firing the bullet, the total momentum must needs also be zero. Therefore, after the shot, m1v1 + m2v2 = 0, where m1 and v1 correspond to the pistol, and m2 and v2 correspond to the bullet.
A 5 g bullet is fired from a 5000g gun If the bullet leaves the gun going 800MS with what speed does the gun recoil?
Using the principle of conservation of momentum, we can calculate that the gun will recoil at 0.08 m/s in the opposite direction of the bullet. The total momentum of the gun and bullet before firing is equal to the total momentum after firing.
A bullet with a mass of 0050kg is fired from a gun of a mass 9kg the bullet has a velocity of 250ms What is the velocity with which the gun recoils?
the conversion of momentum law states that the total momentum of twos systems must be equal therefore M1V1 = M2V2 i am assuming the mass of the bullet is 0.0050 kg and not 50kg so (0.0050 * 250) = ( 9 * X) X = (1.25 / 9) X = 0.139 You can't answer these kind of questions with so few parameters. The bullet diameter, barrel length, powder burn rate all greatly effect the answer. The recoil is caused mainly by the gas exiting the barrel, hence muzzle brakes work.
When a 60g bullet fired from 5kg gun leaves with a speed of 500ms. Find the velocity with which the gun recoils?
By conservation of momentum, the momentum of the gun and bullet system before firing must equal the total momentum after firing. Therefore, the velocity at which the gun recoils can be calculated by using the equation: (mass of bullet * velocity of bullet)/mass of gun = velocity of gun. Substituting the values given: (0.06 kg * 500 m/s) / 5 kg = 6 m/s.
What are some examples of concervation of momentum?
Collisions between billiard balls where the total momentum before the collision is equal to the total momentum after. Recoil of a gun when a bullet is fired, where the forward momentum of the bullet is equal and opposite to the backward momentum of the gun. Ice skaters pushing off each other in opposite directions, resulting in a conservation of momentum system.
When a 3.8 kg rifle fires a 13 gram bullet it experiences a recoil velocity of 2.4ms-1Calculate the velocity of the bullet?
Before the shot, total momentum of the rifle/bullet system is zero. Momentum is conserved, so must total zero after the shot. Magnitude of momentum = m V (mass, speed); we'll take care of direction independently. Momentum of the rifle: m V = (3.8) x (2.4) = 9.12 kg-m/sec backwards. We need momentum of the bullet = 9.12 kg-m/sec forward m V = 9.12 ===> V = ( 9.12 / m ) = ( 9.12 / 0.013 ) = 701.54 m/s forward
Linear of momentum recoil of a rifle formula?
The formula is, quite simply, that the momentum before and after the shot is the same. You can assume that the momentum before the shot is zero (because the rifle and the bullet were not moving), so after the shot, the total momentum will also be zero.
A 5g bullet is fired from a 500g if the bullet leaves the gun going 800ms with what speed does it recoil?
Using the principle of conservation of momentum, the momentum of the bullet before the gunshot is equal to the momentum of the bullet and gun after the shot. Calculating the recoil velocity using this principle shows that the gun will recoil at 1.6 m/s in the opposite direction.
What is the total momentum of cannon and shell before and after firing?
Before the cannon is fired, the momentum is zero. So, after firing, the momentum must still be zero. The momentum of the shell is equal and opposite to that of the cannon, because there is an action and an equal reaction force. Since the momentum difference must be equal: (mv)cannon = (mv)shell Thus, (mv)c - (mv)s = 0 A simple way of looking at it is this is: If the shell is 100 times lighter than the cannon then the shell will move off 100 times faster than the cannon recoils. Remember that, in explosions, the lighter portion moves off faster than the heavier one.
What is and example of conservation of momentum?
In an isolated system the total momentum of a system remains conserved. For example If you fire a bullet from Gun , bullet go forward with some linear momentum and in order to conserve the linear momentum the gun recoils
A bullet is fired from a gun. The speed of the bullet will be about the same as the speed of the recoiling gun if the mass of the bullet equals the mass of the gun?
The mass of a bullet is nowhere near the mass of a gun. A bullet weighs at most a few hundred grains. Most guns weigh at least a couple of pounds, some weigh several pounds (talking about handguns and rifles).
