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What is the combustion of 2-dimethylpropane in Oxygen?
The combustion of 2-dimethylpropane (C5H12) in oxygen involves the reaction between the hydrocarbon and oxygen gas to produce carbon dioxide (CO2) and water (H2O) as the main products. The balanced chemical equation for the combustion of 2-dimethylpropane is: C5H12 + 8O2 -> 5CO2 + 6H2O.
What is the balanced equation for the combustion of heptane in reaction with oxygen?
The balanced equation for the combustion of heptane (C7H16) with oxygen (O2) is: C7H16 + 11O2 → 7CO2 + 8H2O
How many moles of oxygen gas react with 0.100 mol of pentane C5H12?
The balanced chemical equation for the combustion of pentane C5H12 is: C5H12 + 8O2 → 5CO2 + 6H2O Therefore, for every 1 mole of pentane, 8 moles of oxygen gas are required. So, 0.100 mol of pentane will require 0.100 mol * 8 = 0.800 mol of oxygen gas to react completely.
In the reaction 2CO plus O2 equals 2CO2 what is the ratio of moles of oxygen used to moles of CO2 produced?
If you mean atoms then two, if molecules one.
What is heat combustion of pentane?
The heat combustion of pentane involves reacting pentane with oxygen to produce carbon dioxide and water, releasing heat energy in the process. The chemical equation for the combustion of pentane is: C5H12 + 8O2 -> 5CO2 + 6H2O + heat.
What is the coefficient for oxygen in the balanced equation of C5H12 plus O2 equals Co2 plus H2O?
The balanced equation is: C5H12 + 8O2 → 5CO2 + 6H2O. Therefore, the coefficient for oxygen in the balanced equation is 8.
Write a balaced chemical eqution for the combustion of liquid pentane C5H12?
C5h12 + 8o2 --> 5co2 + 6h2o
How many atoms are in 5.58 mol of CO2?
In one (1) molecule CO2 there are 3 atoms ( 1 C-atom and 2 O-atoms), so in 5 molecules CO2 (5CO2) there are 5 x 3 (= 15) atoms. Thus fifteenis the answer to you.
What is the combustion of 2-dimethylpropane in Oxygen?
The combustion of 2-dimethylpropane (C5H12) in oxygen involves the reaction between the hydrocarbon and oxygen gas to produce carbon dioxide (CO2) and water (H2O) as the main products. The balanced chemical equation for the combustion of 2-dimethylpropane is: C5H12 + 8O2 -> 5CO2 + 6H2O.
What is the chemical equation for the complete combustion of 2-methylbutane?
I get 2C6H14+19O2------->12CO2+14H2O
What is produced when you burn pentane?
Burning pentane, C5H12, is a combustion reaction in which pentane and oxygen will react to form carbon dioxide and water. The chemical equation is C5H12 + 8O2 --> 5CO2 + 6H2O
What is the balanced equation for the combustion of heptane in reaction with oxygen?
The balanced equation for the combustion of heptane (C7H16) with oxygen (O2) is: C7H16 + 11O2 → 7CO2 + 8H2O
How many moles of oxygen gas react with 0.100 mol of pentane C5H12?
The balanced chemical equation for the combustion of pentane C5H12 is: C5H12 + 8O2 → 5CO2 + 6H2O Therefore, for every 1 mole of pentane, 8 moles of oxygen gas are required. So, 0.100 mol of pentane will require 0.100 mol * 8 = 0.800 mol of oxygen gas to react completely.
In the reaction 2CO plus O2 equals 2CO2 what is the ratio of moles of oxygen used to moles of CO2 produced?
If you mean atoms then two, if molecules one.
What is heat combustion of pentane?
The heat combustion of pentane involves reacting pentane with oxygen to produce carbon dioxide and water, releasing heat energy in the process. The chemical equation for the combustion of pentane is: C5H12 + 8O2 -> 5CO2 + 6H2O + heat.
Complete and balance the following chemical reactions C5H10OH plus O2?
C5H10OH + 7O2 -> 5CO2 + 6H2O
What is the equation balance or C5H9O plus O2 equals CO2 plus H2O?
First balance H and C:9 H --> 4.5*(2H in H2O) thus multplying by 2to get round figures gives:18 H = 9*(2H in H2O)2*(5 C) --> 10 (C in CO2)So now you've got this incompletely balanced equation (?? O2)2 C5H9O + ?? O2 --> 10 CO2 + 9 H2OThis counts for 10*2 + 9 * 1 Oxygen atoms at right side which will balance with 2 (O in C5H9O) and 27 (O in O2, thus 13.5 O2) and after multplying all molecular's by 2 to get round figures 4 C5H9O + 27 O2 --> 20 CO2 + 18 H2O Control:C: 4*5 = 20 C atoms = 20*1H: 4*9 = 36 H atoms =18*2O: 4*1 + 27*2 = 58 O atoms = 20*2 + 18*1
