In one (1) molecule CO2 there are 3 atoms ( 1 C-atom and 2 O-atoms), so in 5 molecules CO2 (5CO2) there are 5 x 3 (= 15) atoms. Thus fifteenis the answer to you.
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
48,177 134 32.1023 atoms
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
92.4 grams
To find the number of phosphorus atoms in 8.90 mol of copper(II) phosphate (Cu₃(PO₄)₂), we first identify that each formula unit contains 2 phosphorus (P) atoms. Thus, in 8.90 mol of copper(II) phosphate, the total number of phosphorus atoms is calculated as follows: 8.90 mol × 2 P/mol = 17.8 mol of phosphorus atoms. To convert moles to atoms, we multiply by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol): 17.8 mol × (6.022 \times 10^{23}) atoms/mol ≈ (1.07 \times 10^{24}) phosphorus atoms.
There are 1 mol of oxygen atoms in 1 mol of CO2. Therefore, in 0.5 mol of CO2, there are 0.5 mol of oxygen atoms. Number of molecules = 0.5*6.022 *10^23 ≈ 3.011 *10^23 molecules
To calculate the grams of CO2 in 14 mol of the compound, first find the molar mass of CO2: 1 carbon atom (12.01 g/mol) + 2 oxygen atoms (16.00 g/mol each) = 44.01 g/mol. Next, multiply the molar mass of CO2 by the number of moles given (14 mol): 44.01 g/mol x 14 mol = 616.14 grams of CO2.
Carbon Dioxide-CO2 To get molecules, we must convert grams to moles and moles to atoms using Avogadro's number. Molar mass of CO2= C:12.0g+O:16.0gx2=44.0g CO2 25.0g CO2 | 1 mol CO2 | 6.02x10 23 molecules CO2 ------------------------------------------------------------------- = 3.42x10 23 molecules CO2 1 | 44.0g CO2 | 1 mol CO2 Now to get the number of oxygen atoms. Since there are 3 atoms in CO2 and 2 of them are oxygen, we will divide by 3 (1.14x10 23) and multiply by 2 (2.28 x10 23) So the number of oxygen atoms in 25.0 grams of CO2 is 2.28x10 23 or 228 000 000 000 000 000 000 000
To find the number of atoms in 110 grams of CO2, you first need to determine the number of moles by dividing the mass by the molar mass of CO2 (44.01 g/mol). Next, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, there are approximately 2.5 x 10^24 atoms in 110 grams of CO2.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
2.65 mol * 64.07 g/mol = 169.79 g
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
Atomic mass of C = 14g/mol Atomis mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol number of moles = mass / molecular mass number of moles = 220g / 44g/mol = 5.0mol 1 mole of substance contains approximately 6.02 x 10^23 of its particles 5.0 moles of CO2 have 5.0 x 6.02 x 10^23 = 3.01 x 10^24 CO2 molecules. Each CO2 molecule contains 2 oxygen atoms. Total number of Oxygen atom = 2 x 3.01 x 10^24 = 6.02 x 10^24 atoms
The answer is 18,061.1023 atoms.
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.