6.022 x 1023
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
Atomic mass of C = 14g/mol Atomis mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol number of moles = mass / molecular mass number of moles = 220g / 44g/mol = 5.0mol 1 mole of substance contains approximately 6.02 x 10^23 of its particles 5.0 moles of CO2 have 5.0 x 6.02 x 10^23 = 3.01 x 10^24 CO2 molecules. Each CO2 molecule contains 2 oxygen atoms. Total number of Oxygen atom = 2 x 3.01 x 10^24 = 6.02 x 10^24 atoms
Mass of Aluminum Sulfate: 2.74g Molar Mass of Aluminum Sulfate: 342.14 g/mol Therefore, number of moles of Oxygen can be calculated by 2.74g * 12/342.14 g/mol = 0.096 moles Now since u have the moles of Oxygen, the number of oxygen atoms is given by 0.096 mol * (6.02*10^23) particles or atoms/mol that gives u about 5.78 * 10^22 atoms of oxygen
6023*10^23*4.
firstly, you cannot have 1.20105 molecules, it is physically impossible to have a non-integer number of molecules. But I will assume you mean 1.20105 mol. Simply multiply the number of mols of oxygen atoms by avagadros number so 1.20105 mol of n205 = 1.20105*5mol of oxygen atoms. 1.20105 x 5 x 6.022e-23 is your answer
The answer is 18,061.1023 atoms.
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
Carbon Dioxide-CO2 To get molecules, we must convert grams to moles and moles to atoms using Avogadro's number. Molar mass of CO2= C:12.0g+O:16.0gx2=44.0g CO2 25.0g CO2 | 1 mol CO2 | 6.02x10 23 molecules CO2 ------------------------------------------------------------------- = 3.42x10 23 molecules CO2 1 | 44.0g CO2 | 1 mol CO2 Now to get the number of oxygen atoms. Since there are 3 atoms in CO2 and 2 of them are oxygen, we will divide by 3 (1.14x10 23) and multiply by 2 (2.28 x10 23) So the number of oxygen atoms in 25.0 grams of CO2 is 2.28x10 23 or 228 000 000 000 000 000 000 000
Atomic mass of C = 14g/mol Atomis mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol number of moles = mass / molecular mass number of moles = 220g / 44g/mol = 5.0mol 1 mole of substance contains approximately 6.02 x 10^23 of its particles 5.0 moles of CO2 have 5.0 x 6.02 x 10^23 = 3.01 x 10^24 CO2 molecules. Each CO2 molecule contains 2 oxygen atoms. Total number of Oxygen atom = 2 x 3.01 x 10^24 = 6.02 x 10^24 atoms
Mass of Aluminum Sulfate: 2.74g Molar Mass of Aluminum Sulfate: 342.14 g/mol Therefore, number of moles of Oxygen can be calculated by 2.74g * 12/342.14 g/mol = 0.096 moles Now since u have the moles of Oxygen, the number of oxygen atoms is given by 0.096 mol * (6.02*10^23) particles or atoms/mol that gives u about 5.78 * 10^22 atoms of oxygen
The answer is 0,0625 mol.
five
44 grams of CO2 (1 mol CO2 from 1 mol C if enough oxygen, air, is available)
4.5*10^23
6023*10^23*4.
firstly, you cannot have 1.20105 molecules, it is physically impossible to have a non-integer number of molecules. But I will assume you mean 1.20105 mol. Simply multiply the number of mols of oxygen atoms by avagadros number so 1.20105 mol of n205 = 1.20105*5mol of oxygen atoms. 1.20105 x 5 x 6.022e-23 is your answer
C2H4 + 3 O2 --> 2 CO2 + 2 H2OSo 2.16 mol O2 will produce 1.44 mol H2O(and 1.44 mol CO2)because 3:2 = 2.16 : 1.44