6.022 x 1023
To calculate the grams of CO2 in 14 mol of the compound, first find the molar mass of CO2: 1 carbon atom (12.01 g/mol) + 2 oxygen atoms (16.00 g/mol each) = 44.01 g/mol. Next, multiply the molar mass of CO2 by the number of moles given (14 mol): 44.01 g/mol x 14 mol = 616.14 grams of CO2.
To calculate the percentage of oxygen in carbon dioxide, you can use the molecular formula of carbon dioxide (CO2), which consists of one carbon atom and two oxygen atoms. The molar mass of CO2 is 44.01 g/mol (12.01 g/mol for carbon and 2 * 16.00 g/mol for oxygen). To find the percentage of oxygen in CO2, divide the molar mass contribution of oxygen (32.00 g/mol) by the molar mass of CO2 (44.01 g/mol) and multiply by 100. The percentage of oxygen in carbon dioxide is approximately 72.7%.
Atomic mass of C = 14g/mol Atomis mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol number of moles = mass / molecular mass number of moles = 220g / 44g/mol = 5.0mol 1 mole of substance contains approximately 6.02 x 10^23 of its particles 5.0 moles of CO2 have 5.0 x 6.02 x 10^23 = 3.01 x 10^24 CO2 molecules. Each CO2 molecule contains 2 oxygen atoms. Total number of Oxygen atom = 2 x 3.01 x 10^24 = 6.02 x 10^24 atoms
In 4.42 mol of H2O2, there are 26.52 moles of oxygen atoms. This is because each molecule of H2O2 contains two oxygen atoms.
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
Carbon Dioxide-CO2 To get molecules, we must convert grams to moles and moles to atoms using Avogadro's number. Molar mass of CO2= C:12.0g+O:16.0gx2=44.0g CO2 25.0g CO2 | 1 mol CO2 | 6.02x10 23 molecules CO2 ------------------------------------------------------------------- = 3.42x10 23 molecules CO2 1 | 44.0g CO2 | 1 mol CO2 Now to get the number of oxygen atoms. Since there are 3 atoms in CO2 and 2 of them are oxygen, we will divide by 3 (1.14x10 23) and multiply by 2 (2.28 x10 23) So the number of oxygen atoms in 25.0 grams of CO2 is 2.28x10 23 or 228 000 000 000 000 000 000 000
To calculate the grams of CO2 in 14 mol of the compound, first find the molar mass of CO2: 1 carbon atom (12.01 g/mol) + 2 oxygen atoms (16.00 g/mol each) = 44.01 g/mol. Next, multiply the molar mass of CO2 by the number of moles given (14 mol): 44.01 g/mol x 14 mol = 616.14 grams of CO2.
The answer is 18,061.1023 atoms.
To calculate the percentage of oxygen in carbon dioxide, you can use the molecular formula of carbon dioxide (CO2), which consists of one carbon atom and two oxygen atoms. The molar mass of CO2 is 44.01 g/mol (12.01 g/mol for carbon and 2 * 16.00 g/mol for oxygen). To find the percentage of oxygen in CO2, divide the molar mass contribution of oxygen (32.00 g/mol) by the molar mass of CO2 (44.01 g/mol) and multiply by 100. The percentage of oxygen in carbon dioxide is approximately 72.7%.
Atomic mass of C = 14g/mol Atomis mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol number of moles = mass / molecular mass number of moles = 220g / 44g/mol = 5.0mol 1 mole of substance contains approximately 6.02 x 10^23 of its particles 5.0 moles of CO2 have 5.0 x 6.02 x 10^23 = 3.01 x 10^24 CO2 molecules. Each CO2 molecule contains 2 oxygen atoms. Total number of Oxygen atom = 2 x 3.01 x 10^24 = 6.02 x 10^24 atoms
In 4.42 mol of H2O2, there are 26.52 moles of oxygen atoms. This is because each molecule of H2O2 contains two oxygen atoms.
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
There are 4 oxygen atoms in 1 molecule of SO2. Therefore, in 1.25 mol of SO2, there would be 5 moles of oxygen atoms (4 * 1.25 = 5). Using Avogadro's number, we can determine that there are 3.01 x 10^24 oxygen atoms in 1.25 mol of SO2.
firstly, you cannot have 1.20105 molecules, it is physically impossible to have a non-integer number of molecules. But I will assume you mean 1.20105 mol. Simply multiply the number of mols of oxygen atoms by avagadros number so 1.20105 mol of n205 = 1.20105*5mol of oxygen atoms. 1.20105 x 5 x 6.022e-23 is your answer
In one molecule of diphosphorus pentoxide (P2O5), there are 5 oxygen atoms. So, in 5.00 mol of P2O5, there would be 5.00 mol * 5 = 25.00 moles of oxygen atoms.
There are approx 6.02 X 1024 oxygen atoms. --> 5mol CO2 (2mol O2/ 1mol CO2)= 10 mol O2 Then Avagadro's number is used to calculate the number of atoms.... 10 mol O2 (6.02 X 1023/ 1mol) = 6.02 X 1024
When propane is burned in excess oxygen, the balanced chemical equation is: C3H8 + 5 O2 → 3 CO2 + 4 H2O From the equation, we can see that 1 mol of C3H8 produces 3 mol of CO2. Therefore, 10.4 mol of C3H8 will produce 3 x 10.4 = 31.2 mol of CO2.