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How much does CO2 weigh in grams?

carbon= 12.01 oxygen=16*2 12.01+32=44.01 CO2


How many CO2 moles comprise one mole of CO2?

6.02 ten to the power of 23


What is the mass of a half a mole of CO2?

1 mole CO2 has about 44 grams, so half a mole of CO2 equals 22 grams


How many moles of C do you have in the CO2?

1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms.


What is the percent CO2 in sodium bicarbonate?

Sodium Bicarbonate come from absorption of CO2 into NaOH Total reaction is 2NaOH + CO2 -> NaHCO3 + H2O Each mole of NaHCO3 come from absorption of 1 mole CO2 Molecular weight of NaHCO3 is 84 g/mol and CO2 is 44 g/mol It is that 84 g of NaHCO3 had 44 g of CO2 By weight ratio it is 52% CO2 in Sodium Bicarbonate.


How many moles of c are in 000831 moles of co2?

1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.


How much carbon dioxide fits in a lorry?

Assuming you mean gaseous CO2. You can roughly approximate by PV=nRT, where P and T are ambient pressure and temperature and V is the volume of the Lorry. Solve for # of moles, n. (n=PV/(RT)) For weight of CO2, each mole = atomic weight of Carbon plus 2x atomic weight of Oxygen. (44.01 grams / mole)


How many the mole of CO 2 contains?

atomic weight of carbon dioxide is 2 * 16 + 12 = 44 1 kg = 1000 g 1 kg of co2 has 1000/44 = 22.7 moles yeh i think that's wrong lol isn't it 3.37E25?


Does a mole of the element uranium and a mole of CO2 have the same number of particles?

Yes. One mole of anything contains 6.02x10^23 "particles". In the case of the element uranium, it would be 6.02x10^23 atoms of uranium in 1 mole. In the case of CO2, it would be 6.02x10^23 molecules of CO2 in 1 mole.


How many mole of CO2 are formed when 451 mole C8H18 is burned?

When 1 mole of C8H18 is burned, it forms 8 moles of CO2. Therefore, when 451 moles of C8H18 is burned, it will form 8 * 451 = 3608 moles of CO2.


When a 1.25-gram sample of limestone was dissolved in acid 0.44 gram of CO2 was generated if the rock contained no carbonate other than CaCO3 what was the percent of CaCO3 by mass in the limestone?

CaCO3 +2HCl ------------> CaCl2 + CO2 + H2O number of moles of CO2 in .44 grams = .44/ 44 = .01 From equation it is clear that 1 mole of CO2 is produced from CaCO3 = 1 mole .01 mole of CO2 is formed from CaCO3 = .01 mole Weight of .01 mole of CaCO3 is = .01mole *100 g/mole = 1 gram weight % of CaCO3 is = 1*100/ 1.25 = 80 % w/w I've post my answer, so why don't you show that answer here with the question. It's fare. I must be informed about my answer weather it is right or wrong. Please inform me at amitmahalwar@yahoo.com


Does carbon dioxide and oxygen have mass?

Yes. CO2 has a weight of 44g/mol and O2 has a weight of 32g/mol.