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25x2 - 15 is not an equation so it cannot be solved.

25x2+30x+9 25*9=225 15*15=225 15+15=3025x2+15x+15x+9[5*5xx 3*5x] [3*5x 3*3]5x(5x+3)+3(5x+3)(5x+3)(5x+3)Answer: (5x+3)2

50

(5x)2 = 25x2.

25x2 - 10xy + y2 = (5x - y)2

Factorises as (5x-2)(5x-2) so x = 0.4 25x2= 4, -20x = -8 4 - 8 + 4 = 0

The factorization of 25x2 + 40x + 16 is (5x+4)(5x+4).

25x2

25x2 - 36y2 = ( 5x + 6y ) ( 5x - 6y )

25x2 + 40x + 16 = 25x2 + 20x + 20x + 16 = 5x(5x + 4) + 4(5x + 4) = (5x + 4)(5x + 4) or (5x + 4)2

Yes because 25x2-70x+49 = (5x-7)(5x-7) when factored

25x2y

25 x 2 = 50

25x2=50

The absolute value of -15, written as |-15| = 15.

the absolute value of-15 is 15

25x2 to name just one.

I assume you mean 10x - 25x^2 (i.e. to the power of 2, or x squared) If so 10x - 25x^2 = 5x (2 - 5x)

25x2 - 121 can be written as (5x)2 - (11)2 which is of the form a2 - b2. Using the identity a2 - b2 = (a+b)(a-b), we can say 25x2 - 121 = (5x)2 - (11)2 = (5x+11)(5x-11).

If it's written like this (6+4)(6+4) - (25x2) Then the answer will be: 10x10 - 50 100 - 50 = 50

-1

4 and the two equal roots are 2/5 and 2/5

(5x+9y)(5x-9y)

(5x + 12)(5x - 12)

Yes.