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What is the value of g at a distance from the Earth's center equal to 4 times the Earth's radius if the value of g at the earth's surface is about 9.8 meters per second squared?
Wiki User
∙ 12y ago
The gravitation field varies inversely with the square of distance, in this case as measured from the Earth's center. We live on the surface, which is at a distance of 1R where R is the radius. At a distance 4 times greater (4R), the force would fall to 1/4^2 = 1/16 time g.
(9.8)/16 = etc.
Wiki User
∙ 12y ago
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on the surfaceNote:Since the earth's composition is not homogeneous, the gravitational acceleration onthe surface is probably less than what it is some small distance below the surface,but it's certainly greater than at the center.
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That's the Earth's radius. It's about 6378 kilometers at the equator. That's 3963 miles.
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A curved surface on which all points are the same distance from the center is called a sphere.
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7,000 km
If the earths mass doubles and your mass doubles how far from the center of the earth do you have to move so that tour weight will be the same as what it was before the masses changed?
You would have to double your distance from the center of the earth, or about 4,000 miles off the surface.
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it is root of (2*(length of one side squared))
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