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Is there any difference between the value of g at the equator and the poles?
Yes, there is a difference in the value of acceleration due to gravity (g) at the equator and the poles. This is because the Earth is not a perfect sphere and has an oblate shape. At the equator, the centrifugal force due to the Earth's rotation reduces the effective gravity and makes g slightly smaller compared to the poles where this effect is minimal.
What is the value of g when Equator moves towards pole?
The value of acceleration due to gravity (g) decreases as you move from the Equator towards the poles due to the centrifugal force caused by the Earth's rotation. At the Equator, this force counteracts some of the gravitational force, resulting in a lower g value compared to the poles.
Where is maximum value of g?
at the poles
Is the maximum value g at equator?
Yes, the maximum value of acceleration due to gravity (g) is at the equator because the centrifugal force due to the Earth's rotation reduces the effective gravitational force. This results in a maximum g value at the equator compared to other latitudes.
Why is gravity stronger at the poles?
You are closer to the center of the earth at the poles, r is smaller in g=GM/r2
Is the value 'g' same everywhere on the surface of the earth?
No, there are slight variations, due to (a) the fact that some points are closer to Earth's center (a.1, you may be on a mountain, and a.2, the poles are closer to the Earth's center), (b) the centrifugal pseudoforce, which gets stronger as you approach the equator, and (c) any gravitational anomaly caused by an uneven distribution of masses.
What is the value of g being used as a constant and why is this value used?
The value of g depends on latitude because the Earth is wider at the equator than at the poles. g = 9.80612 - 0.025865 cos (2 x latitude) metres/sec/sec It expresses how quickly an object accelerates after being dropped. The formula gives 9.7802 at the equator and 9.8320 at the poles. The weight of a 1 kg mass is g Newtons.
Why does the weight of a substance changes when weighed in a diff parts of world?
it is because earth is not perfectly spherical and also it spins on its Axis. The centrifugal force is greater at the equator and zero on poles. So the apparent weight at equators is lee because of centrifugal force. Also Earth is flattened at the poles which means that there is more acceleration due to gravity at poles[since g=GM/(R^2] In all, ate value of g ranges from around 9.7-9.9 on earth. This causes all the difference.
The weight of an object due to?
The weight is due to the force exerted on the body by the gravitational pull by the earth. If no such gravitational pull on the body, then the body becomes weightless. In free space, very far away from the earth the astronauts experience weightlessness. So if M is the mass of the body, then Mg is the weight of the body. Hence weight depends on the value of 'g'. The value of g is the least at the equatorial region. It will be maximum at the poles. As we go at higher altitudes g value decreases. Same way as we go towards the centre of the earth ie as depth increases, g value decreases.
Is value of g is greater at the poles or at equator?
The expression for acceleration due to gravity isge=GMe/r2Acceleration due to gravity is inversely proportional to the square of the distance between the center of the Earth and the object. The acceleration due to gravity produced in an object on the surface of the Earth is dependent on the radius of the Earth. Earth is not a perfect sphere (slightly bulging out at the equator) its radius decreases as we move from the equator to the poles. At the equator and at sea level its value is about 9.78 m/s2 and at the poles it is 9.83 m/s2. Its mean value is taken as 9.8 m/s2 for all calculations.
What is the value of 'g' if the earth stops rotating?
If the Earth were to stop rotating, the value of 'g' (acceleration due to gravity) would remain approximately the same at the Earth's surface. The rotation of the Earth does not significantly affect the gravitational pull experienced on the surface.
What is the value of G at center of earth?
Zero.
