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If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
About 11 miles per hour.
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
The maximum height of a thrown ball is dependent on the upward portion of the initial velocity. Air friction will slow it somewhat but gravity will cause it to lose most of its upward velocity. The velocity will decrease by 9.8 m/sec for each second of its upward motion, until it reaches zero. At that point, the ball is pulled back toward Earth.
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
About 11 miles per hour.
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
The maximum height of a thrown ball is dependent on the upward portion of the initial velocity. Air friction will slow it somewhat but gravity will cause it to lose most of its upward velocity. The velocity will decrease by 9.8 m/sec for each second of its upward motion, until it reaches zero. At that point, the ball is pulled back toward Earth.
The highest point is the point where the ball's velocity transitions from upward to downward. At that instant, the ball's speed, velocity, momentum, and kinetic energy are all exactly zero.
The thrown ball will (usually) have the highest velocity as the acceleration (resultant of force) used to throw it exceeds that of the other two balls. The ball thrown upward will have a higher downward velocity than the dropped ball even though their accelerations (due to gravity) are the same, as it has more time to travel downward. Although, If the ball thrown upward is thrown high enough, it may even travel faster than the ball thrown downward if the downward throw's force is not enough to beat the ball's terminal velocity (quite a bit of height would be required though).
A the moment when the ball just touches the thrower's hand, it will have the velocity with which it was thrown and the acceleration will be equal to the acceleration due to gravity at the place acting vertically downwards.
A ball thrown down. The thrown ball will have a greater initial velocity and since they experience the same force of gravity, it will always be faster (until they both reach terminal velocity).
The velocity changes from [ V upward ] to [ V downward ].The total change in velocity is [ 2V ].Acceleration = (change in velocity) divided by (time for the change) = 2V/6But the acceleration is just the acceleration of gravity = 9.8 meters / sec2 .9.8 = 2V / 62V = 58.8V = 29.4 meters per second upward
less than the speed it had when thrown upward.
It comes back downward! :) enjoi!