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Of course. Toss a stone straight up. -- From the moment it leaves your hand until the moment it hits the ground, it has constant acceleration ... the acceleration of gravity, around 10 meters per second2. The number isn't important, only the fact that the acceleration of the stone is not zero until it hits the ground. -- Velocity-wise: The stone starts out with some upward velocity, which steadily decreases until it's at the top of its arc, then the velocity becomes downward and increases until the stone hits the ground. -- At the very top of the arc, there is a point where the velocity changes from upward to downward. In order for that to happen, there must be an instant when the velocity is zero. -- But the acceleration is constant and not zero, even at that instant when the velocity is zero.
Simply use the expression v = gt g = 9.8 m/s^2 and t given as 4.5 s So velocity with which the penny hits the ground will be 44.1 m/s
The velocity of an object that leaves the ground is the same as the velocity when it hits the ground on the condition that it is only acted on by gravity, that it lands on an equivalent surface to one that it left in terms of potential energy (altitude]. In a closed system energy must be conserved so an object that leaves the ground with a certain quantity of kinetic energy must hit the ground with the same quantity of kinetic energy as gravity its self which also means that given the surface it lands on is the same in potential energy as the surface it left, the object must have the same velocity as E mv^2/2. Of course the object in real life is subject to friction and various contributing factors so it is only true in an ideal case that the object returns to the ground with the same velocity that it left the ground.
When a body hits an obstacle the force with which it hits the obstacle depends upon---the velocity at the installation of collision bt not on initial velocity.
Ignoring any effects due to air resistance, the speed of the stone is zero at the instant it's dropped, and increases steadily to 78.98 meters per second when it hits the ground. The velocity is directed downward throughout the experiment.
Terminal. It stays at that one velocity til the object hits the ground.
the velocity of the object increases until it hits the ground
A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
20.40
The velocity is gravity acceleration x time or (9.8)(1.5) = 14.7 m/s. The velocity is not dependent on the mass.
Of course. Toss a stone straight up. -- From the moment it leaves your hand until the moment it hits the ground, it has constant acceleration ... the acceleration of gravity, around 10 meters per second2. The number isn't important, only the fact that the acceleration of the stone is not zero until it hits the ground. -- Velocity-wise: The stone starts out with some upward velocity, which steadily decreases until it's at the top of its arc, then the velocity becomes downward and increases until the stone hits the ground. -- At the very top of the arc, there is a point where the velocity changes from upward to downward. In order for that to happen, there must be an instant when the velocity is zero. -- But the acceleration is constant and not zero, even at that instant when the velocity is zero.
it grows from the ground!
No.
in the ground
Simply use the expression v = gt g = 9.8 m/s^2 and t given as 4.5 s So velocity with which the penny hits the ground will be 44.1 m/s
This result is because the wet ball carries more inertia to weight ratio before hitting the ground , it then compresses, loses some of the liquid weight, becomes lighter, and because of the initial inertial force, can therefore leave the ground at a greater velocity
The tomato is not a man made thing, it grows in the ground therefore no one invented it.