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Acceleration is the rate of change of the velocity. Accelerating mean the object is increasing the velocity with time.
velocity is the first derivative of motion, with acceleration being the second; if an object has a constant velocity, then it's acceleration is 0. This is easy to see from everyday life, when you are in a car, you only feel it jerk when you are accelerating but once you've reached your speed you feel nothing.
No, it is uniformly decelerated for the first half and uniformly accelerated motion in the next half in two dimensions.
Newton's first law states that an object at rest stays at rest and an object in motion stays in motion with constant velocity unless acted upon by an unbalanced force. This is also called the law of inertia. So, the forces acting on an object are balanced when the object is not accelerating. This happens when the object is at rest, or when the object is moving at constant velocity. ===================== The forces on an object are balanced when their vector sum is zero.
Speed is scalar (it doesn't have direction), and the magnitude of velocity (a vector). The first derivative of velocity is acceleration, therefore the first derivative of speed is the magnitude of acceleration.
Acceleration is the rate of change of the velocity. Accelerating mean the object is increasing the velocity with time.
Poorly phrased question as the correct answer is merely "Yes, you can." To answer the question probably intended: "How do you distinguish between one object experiencing zero net force and another experiencing non-zero net force?"The first object will be at rest or will have a constant velocity (i.e. speed and direction). The second will have a changing velocity (i.e. a changing speed and/or direction of motion) or, in other words, it will be accelerating (or decelerating).
Quasi-geostropic vertical velocity is a unified equation for the vertical velocity of fluid parcels. This equation involves a system of two coupled differential equations. The first is a vorticity equation which comes from the dynamics of uniformly rotating flows. The second is one that depends on the distinctive properties of the considered fluid.
velocity is the first derivative of motion, with acceleration being the second; if an object has a constant velocity, then it's acceleration is 0. This is easy to see from everyday life, when you are in a car, you only feel it jerk when you are accelerating but once you've reached your speed you feel nothing.
Because you are traveling in a curved path. Acceleration is the time rate of change of velocity. Velocity is a vector quantity. A vector has both a magnitude and a direction. Even if you move at uniform speed in a circle, your velocity is constantly changing, because your direction is changing. The acceleration is also a vector, and points in the direction that the velocity is changing. To speak more precisely, the acceleration is the first time derivative of the velocity, while the velocity is the first time derivative of the position.
No, it is uniformly decelerated for the first half and uniformly accelerated motion in the next half in two dimensions.
First you need to find the two different speeds of the car which is the distance/time. We find that the car first travels at an average of 6ms-1 and then after accelerating has a speed of 10ms-1. Acceleration is the rate of change of velocity over time, our change of velocity being 10-6=4ms-1 and the change in time being stated as 3 seconds we can convert this into... (4/3)ms-2
Galileo
As we roll down a marble on a horizontal floor with some velocity then it is expected to keep rolling on with the same velocity (both magnitude and direction to be constant). But it is brought to rest. So out of two parts in Newtons's first law, the second part cannot be easily demonstrated. That part says that unless an external force acts the uniformly moving body continues to do so.
first law deals with unforced bodies, pushing the car involves an impulse force, once off the cliff the force of gravity takes over , resulting in impulse force until it hits the ground f=m*a but a = velocity change/time, so: force * time/mass= velocity change
Convert 3km/hr2 to km/s2 and 30 km/hr to km/s and apply the equation v f = v o + at and convert the answer to km/hr if desired.
I'd check the CV joints first.