-273 degrees celsius is absolute 0, which cannot be achieved
theoretically, however, the answer to your question is 0 (as goes for any gas, but here's another mind boggler for you: it won't be a gas at absolute 0 either)
more complex explanation below:
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The ideal gas is only ideal, if it follows this mathematical rule (the ideal gas law).
Dividing it by the pressure, you get: Volume = Mass * Some Constant * Temperature / Pressure
If the Temperture is zero you get: Volume = 0 / Pressure = 0
So the volume is 0, if the temperture is 0.
The ideal gas exists only theoreticaly.
Logically the volume can't be 0 and therefor no gas is ideal.
Means the temperature of the gas is 170 degree Celsius
First, you start by listing all of your givens; this will help you know what you have, and what you need to find. V1 = 2.8 L T1 = 25 C + 273 = 300 K. The temperature always has to be in kelvin; so, if you degree Celsius, you have to convert it to kelvin by using the equation K= degrees Celsius + 273 V2 = 15L T2 = ? V1/T1 = V2/T2 By looking at our given, we know you have to use this equation. 2.8L/300K = 15L/T2 We have to cross-multiply. (Basic Algebra) T2 2.8L/2.8L = 4500KL/2.8L T2 = 1607 K 1607 K = 1334 C
yes
V1/T1 = V2/T2 (Charles' Law) T is in Kelvin. Celsius temp plus 273.15 = K T1 = 14 +273 = 287 K T2 = 29 + 273 = 303 K 4.5 / 287 = V2 / 303 V2 = 4.75 L = 4.8 L
This is a mass-mole conversion problem and a gas law problem all rolled into one! First, let's figure out how many moles of CO2 we have. CO2 has 44 grams to the mole, according to the periodic table. If you set up a direct proportion with the given mass, 10.0g, you get 0.23 moles of CO2. Second, figure out what volume 0.23 moles of CO2 will occupy at standard temperature and pressure. Every gas occupies 22.4 liters of space at STP, so 22.4 liters x 0.23 moles = 5.15 liters at STP. Third, convert all temperatures to degrees Kelvin. 27 Celsius = 300 Kelvin, and 0 Celsius (from STP) = 273 Kelvin. Finally, use the gas laws. Set up a direct proportion between the STP volume and temperature and the given temperature, with the new volume as the unknown. Temperature and volume share a direct relationship: 5.15/273=x/300. Solving for x gets you 5.66 liters, which is the answer.
The volume is 2,67 L.
The volume is 0,446 L.
A gas occupies 40.0 L at -123 Celsius. It occupies 80 L of volume at 27 degrees Celsius.
The Mass of a substance will not change with a reduction of temperature … even to -273C.
-273 degrees Celsius is nearly 0 Kelvin or absolute zero. While it is believed that it is impossible to achieve a temperature of absolute zero, all gases will solidify before that happens. A pure gas should form perfect crystals.
The volume is 13,64 L.
If the amount of gas and the pressure remain constant, the volume will decrease by 1/273rd the original volume for each degree Celsius that the temperature decreases.
Kelvin. (K) This can be obtained by adding 273 to any degree that is already in Celsius.
Means the temperature of the gas is 170 degree Celsius
Means the temperature of the gas is 170 degree Celsius
any increase in temperature will cause gas to occupy a larger volume, any decrease will shrink the volume to a point it becomes liquid. further decrease will cause a solid to form. at -273 degrees celsius everything is solid
P1V1/T1 = P2V2/T2Assuming only temperature and volume are changing and pressure will be kept constant:V1/T1 = V2/T2Only Kelvin can be usedV1/273 = V2/523Assume the volume at 0 ºC is 1 unit thenV2 = 1.92 units