One mole of oxygen molecule weighs 32g.
Therefore, 3 moles weigh 32 x 3= 96g
16 grams of oxygen how many moles is 0,5 moles.
1 mole of oxygen weighs 16 grams. So, 1.8 moles would weigh 1.8 x 16 = 28.8g
The formula means, among other things, that there are 7 atoms of oxygen in each mole of the compound. Therefore, in 4.00 moles of the compound, there are 28.00 moles of oxygen atoms. Elemental oxygen usually is diatomic, so that there would be the equivalent of 14 moles of diatomic elemental oxygen.
320 grams of oxygen is the equivalent of 10 moles.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
moles = mass/molar mass The molar mass of an oxygen atom = 16 g mol-1, as there are two oxygen atoms in diatomic oxygen this has to be doubled. 42g / 32g mol-1 = 1.3125 moles
four moles. Approximately. Oxygen has a molecular weight of 16.0 grams per mole so 64 grams divided by 16.0 grams per mole is four moles.
Since oxygen is diatomic it requires 2 moles of oxygen.
16 grams of oxygen how many moles is 0,5 moles.
1 mole of oxygen weighs 16 grams. So, 1.8 moles would weigh 1.8 x 16 = 28.8g
The formula means, among other things, that there are 7 atoms of oxygen in each mole of the compound. Therefore, in 4.00 moles of the compound, there are 28.00 moles of oxygen atoms. Elemental oxygen usually is diatomic, so that there would be the equivalent of 14 moles of diatomic elemental oxygen.
320 grams of oxygen is the equivalent of 10 moles.
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
12.8 grams oxygen (1 mole O/16.0 grams) = 0.800 moles of oxygen
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
0.44g. Molecular weight is 24.3. 0.44/24.3 is 0.0181 moles
#moles = mass/molar mass mass = #moles*molar mass mass = .10 moles*(atomic weight of na+atomic weight of N+3(atomic weight of oxygen)