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Q: What is the weight of one osmole of KCl?
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How many milliosmoles are in an osmole?

There are 1000 milliosmoles in an osmole.


How do you prepare 3.5M KCl solution?

3.5M means 3.5 moles of KCl. 1 mole is the combined molecular weight of the compound per litre. Molecular weight of K (potassium) = 39.10g Molecular weight of Cl (chlorine) = 35.45g So molecular weight of KCl = (39.10 + 35.45) = 74.55g That means that 1 mole of KCL = 74.55 grams per litre If 1 mole of KCL contains 74.55g then 3.5M of KCL will contain 74.55g x 3.5 and so 3.5M of KCL = 260.925g/L


What is the equivalent weight of Ag?

equivalent weight of silver nitrate = 169.87 so 0.1 N Ag NO3 = 16.987 gm /litre of AgNO3 now equivalent weight of KCl = 74.55 so 0.1 N KCl = 7.455 gm/litre so 0.1 N AgNO3 = 0.1N KCl = 7.456 gm of KCl [ not mg ]


Weight of 6 percent KCL Pounds Per gallon?

8.36


How many g of KCl do you need to make 2.5 L of a 10 weight volume solution?

For a 10 % solution you need 250 g KCl.


Help with stoichiometry show steps How many grams of KClO3 must be decomposed to yield 30 grams of oxygen?

2 KClO3 -> KCL + 3O2 Molar weight of O2 = 32 grams/mole (so close it doesn't matter) 30 grams/32grams/mole = 0.9375 moles Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?) now if we have 3 moles of O2 then we have 2 moles of KCl. If we have one mole of O2 then we have 2/3 moles of KCL What ever moles we have of O2 we must multiply it by 2/3 to get the moles of KCl So we have 0.9375moles of O2 x 2/3 = 0.625 moles of KCl So 0.625 moles of KCl x 74.5 grams/mole KCl = 46.5625 grams KCl


How many elements in potassium chloride?

There are two elements in potassium chloride. One atom of potassium and one atom of chlorine react to form potassium chloride.


Formula to potassium chloride?

K+1 Cl-1


How many atoms are in the compound KCI?

two elements and two atoms (potassium and chlorine)In one molecule of KCl, there are two elements (potassium and chlorine).The molecular weight of KCl is 74.55 g / mol.So, 74.55 g of KCl will contain 6.023 x 1023 molecules or 12.046 x 1023 atoms.


How much kcl require for prepaire 3M kcl?

Molar mass of KCl = 74.55g/mol.ie, if you dissolve 74.55g KCl in 1litre (1000 ml) of water, it will be 1M KCl solution.If you want to make 3M KCl solution,Dissolve 3 ×74.55 = 223.65g KCl in 1litre (1000 ml) of water.If you want to make different molar solutions of KCl, just calculate as per below given equation.Weight of KCl to be weighed =Molarity of the solution needed × Molecular weight of KCl (ie, 74.55) × Volume of solution needed in ml / 1000.To prepare 3M KCl in 1 litre, it can be calculated as follows,3 mol × 74.55 g/mol × 1000 ml / 1000 ml = 223.65gByPraveen P Thalichalam, Kasaragod (Dist), Kerala.


Which one of the following compounds is not covalent SCl2 KCl HCl or S2Cl2?

SO2 is definitely NOT ionic


How do you calculate the molecular weight of KCl?

The atomic weight of potassium is 39,0983 g.The atomic weight of chlorine is 25,45 g.The molecular weight of potassium chloride (K + Cl) is 74,5483 g.