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Is 20 percent NEFE acid heavier than 2 percent KCL water?
Yes, a 20 percent NEFE acid solution is heavier than a 2 percent KCL water solution because the density of NEFE acid is higher than that of KCL water. The higher concentration of NEFE acid contributes to its increased weight compared to the lower concentration of KCL in water.
How many ppm is 2 percent KCl?
2 percent KCl is equivalent to 20,000 parts per million (ppm) because 1 percent = 10,000 ppm.
How do you prepare 3.5M KCl solution?
3.5M means 3.5 moles of KCl. 1 mole is the combined molecular weight of the compound per litre. Molecular weight of K (potassium) = 39.10g Molecular weight of Cl (chlorine) = 35.45g So molecular weight of KCl = (39.10 + 35.45) = 74.55g That means that 1 mole of KCL = 74.55 grams per litre If 1 mole of KCL contains 74.55g then 3.5M of KCL will contain 74.55g x 3.5 and so 3.5M of KCL = 260.925g/L
What if a potassium chlorate sample is contaminated with KCL would the experimental percent oxygen be higher or lower than the theoretical percent oxygen?
If a potassium chlorate sample is contaminated with KCl, the experimental percent oxygen would be lower than the theoretical percent oxygen. This is because KCl does not contain oxygen, so the contamination would dilute the amount of oxygen produced during the decomposition of potassium chlorate.
A mixture of KCl and KNO3 is 44.20 percent potassium by mass the percentage of kcl in the mixture is?
To find the percentage of KCl in the mixture, we first need to determine the percentage of potassium coming from KCl. Since the mixture is 44.20% potassium by mass and KCl is 74.55% potassium by mass, we can set up a simple ratio to find the percentage of KCl in the mixture as (74.55% / 100%) * 44.20% = 32.97%. Therefore, the percentage of KCl in the mixture is approximately 32.97%.
Is 20 percent NEFE acid heavier than 2 percent KCL water?
Yes, a 20 percent NEFE acid solution is heavier than a 2 percent KCL water solution because the density of NEFE acid is higher than that of KCL water. The higher concentration of NEFE acid contributes to its increased weight compared to the lower concentration of KCL in water.
How many ppm is 2 percent KCl?
2 percent KCl is equivalent to 20,000 parts per million (ppm) because 1 percent = 10,000 ppm.
How do you prepare 3.5M KCl solution?
3.5M means 3.5 moles of KCl. 1 mole is the combined molecular weight of the compound per litre. Molecular weight of K (potassium) = 39.10g Molecular weight of Cl (chlorine) = 35.45g So molecular weight of KCl = (39.10 + 35.45) = 74.55g That means that 1 mole of KCL = 74.55 grams per litre If 1 mole of KCL contains 74.55g then 3.5M of KCL will contain 74.55g x 3.5 and so 3.5M of KCL = 260.925g/L
What is the Empirical formula of the compound that is 52.7 percent K 47.3 percent Cl?
The empirical formula of the compound with 52.7% K and 47.3% Cl is KCl (potassium chloride). This is because the ratio of potassium to chlorine atoms in the compound is 1:1, leading to the simple formula KCl.
How much 75.66MKCL is required toprepare 1L of solution?
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
What if a potassium chlorate sample is contaminated with KCL would the experimental percent oxygen be higher or lower than the theoretical percent oxygen?
If a potassium chlorate sample is contaminated with KCl, the experimental percent oxygen would be lower than the theoretical percent oxygen. This is because KCl does not contain oxygen, so the contamination would dilute the amount of oxygen produced during the decomposition of potassium chlorate.
Powder of nacl and kcl is dssolved in 80 ml of water and trested with 277 ml of 0.264 molar AgNO3 what is the percent by weight of the NaCl?
Sodium chloride contain chlorine and sodium.
A mixture of KCl and KNO3 is 44.20 percent potassium by mass the percentage of kcl in the mixture is?
To find the percentage of KCl in the mixture, we first need to determine the percentage of potassium coming from KCl. Since the mixture is 44.20% potassium by mass and KCl is 74.55% potassium by mass, we can set up a simple ratio to find the percentage of KCl in the mixture as (74.55% / 100%) * 44.20% = 32.97%. Therefore, the percentage of KCl in the mixture is approximately 32.97%.
How many g of KCl do you need to make 2.5 L of a 10 weight volume solution?
For a 10 % solution you need 250 g KCl.
What is the weight of one osmole of KCl?
The weight of one osmole of KCl is approximately 74.55 grams. This is calculated by adding the atomic weights of potassium (39.10 g/mol) and chlorine (35.45 g/mol) together.
When 200 mL of water are added to 100mL of 12 percent KCL solution the final concentration of KCL is?
The initial amount of KCl in the solution is 12mL (12% of 100mL). When 200mL of water is added, the total volume becomes 300mL. You would then divide the initial amount of KCl (12mL) by the total volume (300mL) and multiply by 100 to get the final concentration of KCl in the solution.
What is the equivalent weight of Ag?
equivalent weight of silver nitrate = 169.87 so 0.1 N Ag NO3 = 16.987 gm /litre of AgNO3 now equivalent weight of KCl = 74.55 so 0.1 N KCl = 7.455 gm/litre so 0.1 N AgNO3 = 0.1N KCl = 7.456 gm of KCl [ not mg ]
