first you have to understand the question! and the answer is yes the acid is heavier than the water
To create a 400 L solution that is 62% acid, you would need 200 L of the 80% acid solution and 200 L of the 30% acid solution. This would result in a final solution with the desired concentration.
Chlorine gas reacts with water to give hypochlorous acid and hydrochloric acid
acid+ metal oxide --> salt + water
Chlorine gas reacts with water to give hypochlorous acid and hydrochloric acid Cl2 + H2O -> HOCl + HCl Chlorine gas reacts with water to give hypochlorous acid and hydrochloric acid
Carbon dioxide is called an acid anhydride because it can react with water to form an acid. When carbon dioxide dissolves in water, it forms carbonic acid. The term "anhydride" refers to a compound formed when a water molecule is removed from an acid.
No, citric acid is not heavier than water. The density of citric acid is lower than that of water, so citric acid will float on the surface of water.
Well, sugar, let me break it down for you. Sulfuric acid is indeed heavier than water, with a density of about 1.84 grams per cubic centimeter compared to water's 1 gram per cubic centimeter. So, in simple terms, if you had a gallon of sulfuric acid and a gallon of water, the sulfuric acid would weigh more. Hope that clears things up for you, honey!
Metaphosphoric acid is often used as a moisture- or water-absorbing reagent. To prepare one-liter of 5 percent metaphosphoric acid, dilute 59 ml of 85 percent metaphosphoric acid with one liter of distilled water.
Acid is a substance that, when added to water, dissociates (dissolves) to release H+ ions into the water. The higher percent of the acid that dissociates, the stronger the acid.
Almost amount of water can be used. The amount you use depends on what purpose the solution will serve. Most dilutions involve using at least as much water as you have of the acid or base, often several times that amount.
well in dilute acid there is 1-10 percent and there will be only 90 percent of water so i was told from a science teacher who studied this
Jorge needs to add 2 liters of water to the 30% acid solution to make a 25% acid solution. This can be calculated using a dilution formula: initial acid amount / final total amount = final acid concentration.
Dilute it with water until it reaches 10 per cent.
Let us assume that x pint water must be mixed with 4 pints of 50 percent acetic acid to produce a mixture that is 33 percent acetic acid. Therefor 4 pint*50 %=(4+x)pint*33% 200 =132 pints + x pints 200-132 = x*33 pints 68 /33 = x pints So x = 2.06 pints Answer : 2.06 pint water must be mixed with 4 pints of 50 percent acetic acid to produce a mixture that is 33 percent acetic acid.
This is a homogeneous mixture, as the two components (water and acetic acid) are evenly distributed throughout the solution and cannot be easily distinguished.
the more the battery is charged, the less water. dead battery is close to 100% water. charged battery is close to 90 - 100% sufuric acid
4.84