0
What else can I help you with?
If more solvent is added to a solution?
Adding solvent will make a solution more diluted. Think of it this way. Take water (solvent) and dissolve salt into it (solute). In order to dilute or increase the ratio of solvent to solute, you would add more water.
How do you prepare a 500mL of 1M of NaCl solutuion?
If you need to make just 100mL, then you need 1 tenth of a liter that is 5M. If you were to make 1L of 5 molar NaCl, you would need 5 times the molar mass of NaCl (58.44g/mol) dissolved in 1L of water. Thus for 1L of a 5M solution you need 5 * 58.44g, or 292.2 grams of NaCl. However, since we only want 100mL, which is 1/10 of a Liter, we also only need 1/10 the amount of NaCl, or 292.2 / 10, which is 29.22g. So, measure out 29.22g NaCl, and dissolve completly in a volume less than 100mL, say 80mL, then bring the final volume up to 100mL. You now have 100mL of a 5M NaCl solution.
What would happen to the concentration of hydrogen ions in a solution of a strong acid if an equal number of hydroxide ions were added to the solution?
The concentration of hydrogen ions would decrease because when hydroxide ions react with hydrogen ions, they form water. This reaction reduces the overall concentration of hydrogen ions in the solution.
What is the concentration in mv percent of a solution prepared from 50 g NaCl and 2.5 L of water?
Chemists often express the concentration of an unsaturated solution as the mass of solute dissolved per volume of the solution. This type of concentration is expressed as percent relationship. The mass/volume percent is also referred to as the percent (m/v)The solubility of NaCl at room temperature is 36g/100mL. Clearly in the problem stated above, the NaCl-H2O solution is quite dilute and much below the saturation point.The following formula is useful in determining the mass/volume percent:m/v% = [ mass solute(g) / volume of solution (mL) ] x 100%2.5 L can be expressed in mL.2.5L = 2500mLtherefore the m/v% = (50g NaCl / 2500 mL H2O) * 100%m/v% = 0.02 * 100%m/v% = 2%Therefore the concentration of this solution as a m/v percent is 2%.Note1: The question is a bit misleading since it never states what is the desired final volume of the NaCl-H2O solution. The required number of grams of solute should never be added directly to the desired final volume of solvent, because volume generally changes when solutions are made.When preparing solutions, the correct procedure is to dissolve the solute in a volume of solvent smaller than the final desired volume. The resulting solution is then diluted to the desired final volume by addition of more solvent. See note 2 for preparation.Note2: To actually prepare this solution, it would be ideal to have the appropriate volumetric glassware. Lets say all you had was a 2L volumetric flask, a 500mL volumetric flask and a 3L storage container.What you could do is add the 50g of NaCl to the empty 2L volumetric flask, then fill the flask with water until you reach the 2L calibration mark. You could then transfer that solution to the 3L storage container.You would then fill the 500mL volumetric flask with water to its calibration mark, and then transfer the water to the storage container. The result would be a 2% (m/v) saline solution with a final volume of 2.5L contained in a 3L storage container.
Solution is prepared by dissolving 13.3g ammonium sulfate in enough water to make 100.0 mL of stock solution A 12.00 mL sample of this stock solution is added 57.00 mL of water Calculate the concen?
The concentration of the resulting solution is calculated by adding the mass of the solute to the final volume of the solution. In this case, the 12.00 mL sample contains 13.3g of ammonium sulfate. When diluted to a total volume of 12.00 mL + 57.00 mL = 69.00 mL, the concentration of the resulting solution can be determined.
How much grams of ferric chloride to be added in 100ml of water to get 2 percent solution?
To prepare a 2% solution of ferric chloride in 100ml of water, you would need to add 2 grams of ferric chloride. This is calculated by multiplying the volume of the solution (100ml) by the desired concentration (2%) and converting it to grams.
How much grams of ammoinum thiocyanate to be added in 100ml of water to get 1 percent of solution?
Very simply 1g of ammonium thiocyanate and 100g (100ml) of water!
How many ml should be added to 100ml of a 25 percent solution to get produce a 20 percent solution?
add 25ml more of solution x * 20 = 100 * 25 x = 25
500mg of a drug was added to a 100 mL IV bag what is the percent strength now of the solution?
600
What is the final percent concentration of the solution when 600 ml of 100 percent methanol added to 4400 ml of water?
The final percent concentration of the solution would be approximately 12.0% methanol. This is calculated by dividing the volume of methanol by the total volume of the solution (600 ml / 5000 ml) and then multiplying by 100 to get the percentage.
If A hospital pharmacist dilutes a vial containing 1 gram of antibiotic with 10ml of water and the solution is then added to 100 ml of D5W what is the concentration in mgml of the antibiotic in theD5W?
Xml/1gm=100mL/5g=20mL Xgm/10mL=5gm/100mL=.5gm =.5g/20mL
What does 0 percent dilution mean?
0 percent dilution means that no additional solvent or liquid has been added to a solution. The solution remains in its original concentration without any dilution.
When more solvent is added to a solution to decrease its concentration it is called?
When more solvent is added to a solution to decrease its concentration, it is called dilution. Dilution involves reducing the concentration of solute particles within the solution by adding more solvent to increase the total volume.
How does concentration change after every spoon full of salt is added after the solution is saturated?
The concentration of the salt solution does NOT change- it is saturated.
When more solvent is added to a solution what happens to the concentration?
When more solvent is added to a solution, the concentration of the solute decreases. This is because the total volume of the solution increases while the amount of solute remains constant, resulting in a more diluted solution.
How much of a ten percent solution should be added to two cups of twenty percent solution to make a twelve percent solution?
2%
How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
