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What is the concentration in mv percent of a solution prepared from 50 g NaCl and 2.5 L of water?
Wiki User
∙ 12y ago
Chemists often express the concentration of an unsaturated solution as the mass of solute dissolved per volume of the solution. This type of concentration is expressed as percent relationship. The mass/volume percent is also referred to as the percent (m/v)
The solubility of NaCl at room temperature is 36g/100mL. Clearly in the problem stated above, the NaCl-H2O solution is quite dilute and much below the saturation point.
The following formula is useful in determining the mass/volume percent:
m/v% = [ mass solute(g) / volume of solution (mL) ] x 100%
2.5 L can be expressed in mL.
2.5L = 2500mL
therefore the m/v% = (50g NaCl / 2500 mL H2O) * 100%
m/v% = 0.02 * 100%
m/v% = 2%
Therefore the concentration of this solution as a m/v percent is 2%.
Note1: The question is a bit misleading since it never states what is the desired final volume of the NaCl-H2O solution. The required number of grams of solute should never be added directly to the desired final volume of solvent, because volume generally changes when solutions are made.
When preparing solutions, the correct procedure is to dissolve the solute in a volume of solvent smaller than the final desired volume. The resulting solution is then diluted to the desired final volume by addition of more solvent. See note 2 for preparation.
Note2: To actually prepare this solution, it would be ideal to have the appropriate volumetric glassware. Lets say all you had was a 2L volumetric flask, a 500mL volumetric flask and a 3L storage container.
What you could do is add the 50g of NaCl to the empty 2L volumetric flask, then fill the flask with water until you reach the 2L calibration mark. You could then transfer that solution to the 3L storage container.
You would then fill the 500mL volumetric flask with water to its calibration mark, and then transfer the water to the storage container. The result would be a 2% (m/v) saline solution with a final volume of 2.5L contained in a 3L storage container.
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∙ 12y ago
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