KCl
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
1 mole of hydrochloric acid reacts with 1 mole of potassium hydroxide in a 1:1 ratio. Therefore, 0.100 mole of hydrochloric acid would require 0.100 mole of potassium hydroxide to completely neutralize it.
The moles of KHCO3 and KCl produced should be the same because they are stoichiometrically related in the chemical reaction that produces them. For every mole of KHCO3 that reacts, it produces one mole of KCl. This means that the number of moles of KHCO3 consumed is equal to the number of moles of KCl produced in the reaction.
Balanced equation and potassium limits and drives the reaction.2K + Cl2 -> 2KCl6.75 grams K (1 mole K/39.10 grams)(2 mole KCl/2 mole K)(74.55 grams /1 mole KCl)= 12.9 grams potassium chloride produced==============================
To determine the mole-to-mole ratio in a chemical reaction, you can use the coefficients of the balanced chemical equation. The coefficients represent the number of moles of each substance involved in the reaction. By comparing the coefficients of the reactants and products, you can determine the mole-to-mole ratio between them.
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
1 mole of hydrochloric acid reacts with 1 mole of potassium hydroxide in a 1:1 ratio. Therefore, 0.100 mole of hydrochloric acid would require 0.100 mole of potassium hydroxide to completely neutralize it.
The moles of KHCO3 and KCl produced should be the same because they are stoichiometrically related in the chemical reaction that produces them. For every mole of KHCO3 that reacts, it produces one mole of KCl. This means that the number of moles of KHCO3 consumed is equal to the number of moles of KCl produced in the reaction.
To determine the amount of KCl decomposed, first calculate the moles of O2 produced using its molar mass. Then use the mole ratio of O2 to KCl in the reaction (3:2) to find the moles of KCl decomposed. Finally, convert the moles of KCl decomposed to grams using its molar mass to get the final answer.
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
To prepare a 0.01M KCl (potassium chloride) solution in 1 liter, you would need to dissolve 0.74 grams of KCl in enough water to make 1 liter of solution. This can be calculated using the formula: moles = Molarity x Volume (in liters) x Molecular weight of KCl.
7: Molecules of HCl and KCl have the same number, 1, or chlorine atoms per mole; therefore, if HCl reacts completely with potassium, the same number of moles of potassium chloride as the number of moles of hydrogen chloride present will be formed. (For an ionic compound such as KCl, the term "formula unit" is preferable to "mole", but the mathematical consequences are the same.)
3.5M means 3.5 moles of KCl. 1 mole is the combined molecular weight of the compound per litre. Molecular weight of K (potassium) = 39.10g Molecular weight of Cl (chlorine) = 35.45g So molecular weight of KCl = (39.10 + 35.45) = 74.55g That means that 1 mole of KCL = 74.55 grams per litre If 1 mole of KCL contains 74.55g then 3.5M of KCL will contain 74.55g x 3.5 and so 3.5M of KCL = 260.925g/L
Balanced equation and potassium limits and drives the reaction.2K + Cl2 -> 2KCl6.75 grams K (1 mole K/39.10 grams)(2 mole KCl/2 mole K)(74.55 grams /1 mole KCl)= 12.9 grams potassium chloride produced==============================
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
The experimental mole ratio is obtained from actual experimental data, while the theoretical mole ratio is calculated based on the balanced chemical equation. Comparing the two can reveal discrepancies and provide insight into the accuracy of the experimental results or any potential sources of error in the experiment.
To determine the mole-to-mole ratio in a chemical reaction, you can use the coefficients of the balanced chemical equation. The coefficients represent the number of moles of each substance involved in the reaction. By comparing the coefficients of the reactants and products, you can determine the mole-to-mole ratio between them.